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**Physics, Astronomy & Cosmology / Re: Bell's Inequality error...**

« **on:**22/11/2016 07:59:19 »

The error lies in the nature of treating the cases where all doors are equal as simply 1/3 of all options and for the other 1/3 where they are the same as equivalent in weight. The probabilities should break down as:

1/3 (of non-similar selected doors for 2/3 different color) <--> 50% different

The bolded are what make up the cases as 2/3 when that first 1/3 must be split or the other two divided.

For any one door selected by both Scully, say, Mulder can pick the same door and automatically is assured of a match. But this 'appears' as it should be treated as ONE probability:

If Scully picks door T and it is blue, and Mulder picks door T, it can ONLY BE 1 x blue.

But if Mulder picked any of the other doors instead, he has 1/2 x blue or 1/2 x red.

So this would be more appropriately be:

1/3 x 1/2 = probability for non-similar door selection for differences = 1/6

Thus, when corrected, should 50% in experiment demonstrate they are the same, you have to treat this as constituting the 1/3 + 1/6 weighted parts (= 1/2) in actuality!

This definitively disproves Bell's theorem to be useful to prove anything!!

**1/3**(all 3 doors equal color and both select the same door) <--> 100% same**1/3**(of non-similar selected doors for 2/3 same color) <--> 50% same1/3 (of non-similar selected doors for 2/3 different color) <--> 50% different

The bolded are what make up the cases as 2/3 when that first 1/3 must be split or the other two divided.

For any one door selected by both Scully, say, Mulder can pick the same door and automatically is assured of a match. But this 'appears' as it should be treated as ONE probability:

If Scully picks door T and it is blue, and Mulder picks door T, it can ONLY BE 1 x blue.

But if Mulder picked any of the other doors instead, he has 1/2 x blue or 1/2 x red.

So this would be more appropriately be:

**1/3 x 1**= probability for identical door selection when all 3 the same = 1/3**1/3 x 1/2**= probability for non-similar door selection for the same = 1/61/3 x 1/2 = probability for non-similar door selection for differences = 1/6

Thus, when corrected, should 50% in experiment demonstrate they are the same, you have to treat this as constituting the 1/3 + 1/6 weighted parts (= 1/2) in actuality!

This definitively disproves Bell's theorem to be useful to prove anything!!

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