« on: 30/01/2019 17:09:29 »
Why do you refer to Uranium nucleus?
Because I was able to find a value for its diameter. I was only using it as an upper bound on the possible size of the helium-3 nucleus because I was unable to find any literature stating the size of the helium-3 nucleus.
I don't know how you get those numbers
The value for the diameter of atomic nuclei came from the "Table of experimental nuclear ground state charge radii": https://www.sciencedirect.com/science/article/pii/S0092640X12000265?via%3Dihub
and how to isolate a single atom nucleus from interaction with its environment, including orbiting electrons and adjacent other atoms to measure the binding energy.
The binding energy is calculated from the difference between the mass of an atomic nucleus and each of its component particles. The mass of an atomic nucleus can be determined using mass spectrometry: https://www.livescience.com/20581-weigh-atom.html
What are the lepton numbers of those particles?
Protons have a lepton number of zero, whereas electrons have a lepton number (more specifically, electron number), of one. The violation mentioned in the article is between specific forms of lepton number (i.e. changing from muon number to electron number). However, the total lepton number is still the same. In other cases where lepton number is violated, the total baryon number minus lepton number (B-L) is still conserved: https://en.wikipedia.org/wiki/B_%E2%88%92_L
Your model violates B-L because the baryon number remains the same before and after decay whereas the lepton number changes.
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