« on: 16/04/2020 23:11:06 »
what is the position of the front of the train car for x=0.2598cs and t=2.3s in the train frame coordinates?I didn't do any calculations to 4 digits of precision. The yellow lines show lines of simultaneity along the changing frame of the train as it turns around. You can see the line from that event being simultaneous with the short duration at t'=4 x'=0 measured at the front of the train.QuoteThe Triplets challenge - is the right triplet going to say that the left triplet proper time is the same as his/her (the right triplet)?Proper time is frame independent, so all observers will agree that the proper times of the left and right worldlines between events A and B are identical.QuoteIf the proper time is not the same then the middle triplet reference frame analysis is useless, essentially, we do not have physics.Maybe you should not only read, but actually comprehend that book you linked.
If the left triplet proper time is observed/analyzed as to be same as the proper time of the right triplet from the right triplet frame then we need to see those claims/analysis because according to MCF (momentarily co-moving inertial reference frame) the left frame is moving and the Lorentz Transformation does not allow for the proper time to be the same.QuoteThe claim is:Have fun justifying these claims.
- if the left time is not the same from the right frame point of view ... then we do not have physics because it contradicts the middle triplet's frame.
- if the left time is the same as the right frame time ... then we do not have the Lorentz Transformation, we do not have the Relativity
using this: http://www.trell.org/div/minkowski.html
The time on the train car is 4.15s'.
The train starts to decelerate at 2.3s according to your calculations.
The front of the train car is already past the turning point for the platform 2.3s.
What are you trying to show us with your spacetime diagram?
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