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**New Theories / Could mass reach the speed of light ?**

« **on:**

**Yesterday**at 12:48:28 »

A mass at stationary relapse distance equals zero , time is zero, time is frozen .

According to special theory of relativity , as the mass gets faster the distance it travels decrease " A mass at stationary relapse distance equals zero , time is zero, time is frozen .

According to special theory of relativity , as the mass gets faster the distance it travels decrease " length contraction" and time delays, if the object reach in its speed the speed of light it will in fact stops " the decrement in length will reach its minimum which is zero, time stops, doesn't that means the mass at stationary is this case?

What I mean is as the mass velocity increases its kinetic energy increase and at its smallest length contraction the length will equal zero.

L=L0√(1-v²/c²) by substituting v=c ,we could actually obtain a zero contracted length.

The object in the number line moving from 2 to 3 will reach the 3 even if it covers infinite fractions

.

What I A mass at stationary relapse distance equals zero , time is zero, time is frozen .

According to special theory of relativity , as the mass gets faster the distance it travels decrease " length contraction" and time delays, if the object reach in its speed the speed of light it will in fact stops " the descerment in length will reach its minimum which is zero and time stops, doesn't that means the mass at stationary is this case?

What I mean is as the mass velocity increase its kinetic energy increase and at its smallest length contraction the length will equal zero.

L=L0√(1-v²/c²) by substituting v=c ,we could actually obtain a zero contraacted length.

The object in the number line moving from 2 to 3 will reach the 3 even if it covers infinite fractions

.

What I propose here is the mass of an object "the frozen mass" will decrease as the kinetic energy increase , it will reach zero at a time " without energy conservative violation" at the time the mass reaches zero the kinetic energy will behave as a photon and will move at the speed of light. The idea of zero mass is obvious when mass converts to energy " E=mcc²"However the idea of increment in mass is mysterious .

The mass decreases and its contained energy is lost to be added to the total energy of the kinetic energy.

Light is massless and travels at the speed c if we substitute m=0 and v=c:

m=m0/√(1-v²/c²) , v=c , m=0,

0=0/0 the equation an't be applied to a photon , if the kinetic energy of a mass increases and the mass disappeared the equation also can't be applied to such case.

It is for sure that according to my argument in the above thread link, the zero contracted length reaches zero, even if kinetic energy goes to infinity, if the above equation doesn't apply for a photon and doesn't apply to the cases I mentioned, then we can't be sure if the mass will move at the speed of light or not by using the equation .

A photon is massless and moves at speed c, an object loses it mass mass when moving close to c, and its mass disappears becoming a photon then it moves at the speed of c.

m=m0 * √(1-v²/c²) , v=c then m=0 this doesn't affect the general relativity kinetic energy equation:

K.E=m0c²/√(1-v²/c²) +mc², It could be :

K.K = E0/√(1-v²/c²) +E0, E0 is energy of the rest mass which doesn't change even if the mass decrease" m0 will convert to E0"

I proposes here is the mass of an object "the frozen mass" will decrease as the kinetic energy increase , it will reach zero at a time " without energy conservative violation" at the time the mass reaches zero the kinetic energy will behave as a photon and will move at the speed of light. The idea of zero mass is obvious when mass converts to energy " E=mc²"However the idea of increment in mass is mysterious .

The mass decreases and its contained energy is lost to be added to the total energy of the kinetic energy.

Light is massless and travels at the speed c if we substitute m=0 and v=c:

m=m0/√(1-v²/c²) , v=c , m=0,

0=0/0 the equation can't be applied to a photon , if the kinetic energy of a mass increases and the mass disappeared the equation also can't be applied to such case.

It is for sure that according to my argument in the above thread link, the zero contracted length reaches zero, even if kinetic energy goes to infinity, if the above equation doesn't apply for a photon and doesn't apply to the cases I mentioned, then we can't be sure if the mass will move at the speed of light or not by using the equation .

A photon is massless and moves at speed c, an object loses it mass mass when moving close to c, and its mass disappears becoming a photon then it moves at the speed of c.

My equation is :

K.E=m0c²/√(1-v²/c²) +m0c², It could be :

E0/√(1-v²/c²) +E0, E0 is energy of the rest mass which doesn't change even if the mass decrease" m0 will convert to E0"

What I mean is as the mass velocity increase its kinetic energy increase and at its smallest length contraction the length will equal zero.

L=L0√(1-v²/c²) by substituting v=c ,we could actually obtain a zero contracted length.

I propose that if the length approaches zero , it will reach the zero .and if the mass approaches zero it will reach that value .

The object in the number line moving from 2 to 3 will reach the 3 even if it covers infinite fractions

.

What I propose here is the mass of an object "the frozen mass" will decrease as the kinetic energy increase , it will reach zero at a time " without energy conservative violation" at the time the mass reaches zero the kinetic energy will behave as a photon and will move at the speed of light. The idea of zero mass is obvious when mass converts to energy " E=mc²"

The mass decreases and its contained energy is lost to be added to the total energy of the kinetic energy.

Light is masseless and travels at the speed c if we substitute m=0 and v=c:

m=m0/√(1-v²/c²) , v=c , m=0,

0=0/0 the equation an't be applied to a photon , if the kinetic energy of a mass increases and the mass disappeared the equation also can't be applied to such case.

if the above equation doesn't apply for a photon and doesn't apply to the cases I mentioned, then we can't be sure if the mass will move at the speed of light or not by using the equation .

A photon is massless and moves at speed c, an object loses it mass mass when moving close to c, and its mass disappears becoming a photon then it moves at the speed of c.

My equation :

m=m0 * √(1-v²/c²) , v=c then m=0

This doesn't affect the general relativity kinetic energy equation:

K.E=m0c²/√(1-v²/c²) +m0c², It could be :

E0/√(1-v²/c²) +E0, E0 is energy of the rest mass which doesn't change even if the mass decrease" m0 will convert to E0"

According to special theory of relativity , as the mass gets faster the distance it travels decrease " A mass at stationary relapse distance equals zero , time is zero, time is frozen .

According to special theory of relativity , as the mass gets faster the distance it travels decrease " length contraction" and time delays, if the object reach in its speed the speed of light it will in fact stops " the decrement in length will reach its minimum which is zero, time stops, doesn't that means the mass at stationary is this case?

What I mean is as the mass velocity increases its kinetic energy increase and at its smallest length contraction the length will equal zero.

L=L0√(1-v²/c²) by substituting v=c ,we could actually obtain a zero contracted length.

The object in the number line moving from 2 to 3 will reach the 3 even if it covers infinite fractions

.

What I A mass at stationary relapse distance equals zero , time is zero, time is frozen .

According to special theory of relativity , as the mass gets faster the distance it travels decrease " length contraction" and time delays, if the object reach in its speed the speed of light it will in fact stops " the descerment in length will reach its minimum which is zero and time stops, doesn't that means the mass at stationary is this case?

What I mean is as the mass velocity increase its kinetic energy increase and at its smallest length contraction the length will equal zero.

L=L0√(1-v²/c²) by substituting v=c ,we could actually obtain a zero contraacted length.

The object in the number line moving from 2 to 3 will reach the 3 even if it covers infinite fractions

.

What I propose here is the mass of an object "the frozen mass" will decrease as the kinetic energy increase , it will reach zero at a time " without energy conservative violation" at the time the mass reaches zero the kinetic energy will behave as a photon and will move at the speed of light. The idea of zero mass is obvious when mass converts to energy " E=mcc²"However the idea of increment in mass is mysterious .

The mass decreases and its contained energy is lost to be added to the total energy of the kinetic energy.

Light is massless and travels at the speed c if we substitute m=0 and v=c:

m=m0/√(1-v²/c²) , v=c , m=0,

0=0/0 the equation an't be applied to a photon , if the kinetic energy of a mass increases and the mass disappeared the equation also can't be applied to such case.

It is for sure that according to my argument in the above thread link, the zero contracted length reaches zero, even if kinetic energy goes to infinity, if the above equation doesn't apply for a photon and doesn't apply to the cases I mentioned, then we can't be sure if the mass will move at the speed of light or not by using the equation .

A photon is massless and moves at speed c, an object loses it mass mass when moving close to c, and its mass disappears becoming a photon then it moves at the speed of c.

m=m0 * √(1-v²/c²) , v=c then m=0 this doesn't affect the general relativity kinetic energy equation:

K.E=m0c²/√(1-v²/c²) +mc², It could be :

K.K = E0/√(1-v²/c²) +E0, E0 is energy of the rest mass which doesn't change even if the mass decrease" m0 will convert to E0"

I proposes here is the mass of an object "the frozen mass" will decrease as the kinetic energy increase , it will reach zero at a time " without energy conservative violation" at the time the mass reaches zero the kinetic energy will behave as a photon and will move at the speed of light. The idea of zero mass is obvious when mass converts to energy " E=mc²"However the idea of increment in mass is mysterious .

The mass decreases and its contained energy is lost to be added to the total energy of the kinetic energy.

Light is massless and travels at the speed c if we substitute m=0 and v=c:

m=m0/√(1-v²/c²) , v=c , m=0,

0=0/0 the equation can't be applied to a photon , if the kinetic energy of a mass increases and the mass disappeared the equation also can't be applied to such case.

It is for sure that according to my argument in the above thread link, the zero contracted length reaches zero, even if kinetic energy goes to infinity, if the above equation doesn't apply for a photon and doesn't apply to the cases I mentioned, then we can't be sure if the mass will move at the speed of light or not by using the equation .

A photon is massless and moves at speed c, an object loses it mass mass when moving close to c, and its mass disappears becoming a photon then it moves at the speed of c.

My equation is :

**m=m0 * √(1-v²/c²)**, v=c then m=0 this doesn't affect the general relativity kinetic energy equation:K.E=m0c²/√(1-v²/c²) +m0c², It could be :

E0/√(1-v²/c²) +E0, E0 is energy of the rest mass which doesn't change even if the mass decrease" m0 will convert to E0"

What I mean is as the mass velocity increase its kinetic energy increase and at its smallest length contraction the length will equal zero.

L=L0√(1-v²/c²) by substituting v=c ,we could actually obtain a zero contracted length.

I propose that if the length approaches zero , it will reach the zero .and if the mass approaches zero it will reach that value .

The object in the number line moving from 2 to 3 will reach the 3 even if it covers infinite fractions

.

What I propose here is the mass of an object "the frozen mass" will decrease as the kinetic energy increase , it will reach zero at a time " without energy conservative violation" at the time the mass reaches zero the kinetic energy will behave as a photon and will move at the speed of light. The idea of zero mass is obvious when mass converts to energy " E=mc²"

The mass decreases and its contained energy is lost to be added to the total energy of the kinetic energy.

Light is masseless and travels at the speed c if we substitute m=0 and v=c:

m=m0/√(1-v²/c²) , v=c , m=0,

0=0/0 the equation an't be applied to a photon , if the kinetic energy of a mass increases and the mass disappeared the equation also can't be applied to such case.

if the above equation doesn't apply for a photon and doesn't apply to the cases I mentioned, then we can't be sure if the mass will move at the speed of light or not by using the equation .

A photon is massless and moves at speed c, an object loses it mass mass when moving close to c, and its mass disappears becoming a photon then it moves at the speed of c.

My equation :

m=m0 * √(1-v²/c²) , v=c then m=0

This doesn't affect the general relativity kinetic energy equation:

K.E=m0c²/√(1-v²/c²) +m0c², It could be :

E0/√(1-v²/c²) +E0, E0 is energy of the rest mass which doesn't change even if the mass decrease" m0 will convert to E0"