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Hi allI have been given this formula: Ba(HC2O4)2 for Barium Oxalate, which i need to prepare and crystalize into salt form.I have established that i need to use oxalic acid for the process for which i have found many variations as to what the formula is, the text book says (COOH)2 but i cannot seem to balance the equation when using Barium and oxalic acid, and i cannot find anywhere that says how to prepare it.I am thinking to mix into heating bowl and heat gently to evapourate and then leave to crystalize, is this safe to do?The equation i got (which isn't balanced at all!!) is:Ba + (COOH)2 ----------> Ba(HC2O4)2I HAVE to use the Ba(HC2O4)2 as this was the one thing i was given by my tutor.Can anyone help me please? 
ok none of these seem to be balancing to me! eg:Ba(OH)2 + 2H2C2O4 = Ba(HC2O4)2 + 2H2OBA= 1 > Ba = 1C= 2 > C=2H=6 > H=6BUTO=6 > O=9??AND:Ba + 2H2C2O4 = Ba(HC2O4)2 +H2 (which is the equation i would expect to make)Ba=1 > Ba=1H=4 > H=4C=2 > C=2BUTO=4 >O=8???Am i wrong?
so would this work?Ba + (H2C2O4)2 = Ba (HC2O4)2 + H2 [?]