I have a question I THOUGH would be easy to answer, yet the more I dug, the more confused I got. The complications arouse in the usual places; conversions and standardizations.

The question:

What's cheaper to do: heat 3 cups of water in a typical kettle on a typical kitchen gas stove, or heat the water in an electric kettle? And by how much? What is the approximate cost of each's process?

Some empirical particulars:

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--stove kettle is typical half-dome style steel kettle, 8 inches across the base. Not particularly flimsy, just a typical thin-gauge steel, maybe a shade thicker gauge on the base.

--gas source is a typical gas range burner (GE range).

--from user manuals I've seen on the web, and experience w/ other ranges, the burner's output LOOKS TO BE 6000 BTU rating. This is just a guess..... Some ratings I've seen are 5,500 BTU, to 16,00 BTU/burner. This burner seems to be on the less powerful (?) side ....

--Altitude is 7K feet (Evergreen, CO)

--true natural gas, not propane.

--XCel energy rates on natural gas: $0.07 per therm (Th). I understand this to be 7 cents/100 ft gas?

--it takes precisely 9 minutes to heat the 3 cups water in the kettle.

--it is evident a large portion of the HEAT escapes. The heat goes around the kettle, escaping into the air.

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Contrasts to an electric kettle:

1000w-rated kettle, taller than wide, not too flimsy metal, a bit thicker than the kettle.

--takes 1.5 minutes to heat the 3 cups of water.

--XCel energy residential rates electricity: $0.033 /kWh.

REASON: I'm hazarding its #1) cheaper to heat w/ an electric kettle, and #2) more energy efficient. --And I believe its more efficient by an order of magnitude.

I'm not necessarily assuming its CHEAPER by an order of magnitude, but is more efficient to heat via the electric kettle by far.

ADDED COMPLICATOR: secondarily, factor in the complete power-budget if we consider the energy cost of generating the electricity and delivering it TO the outlet the kettle is plugged into. This MUST skew the analysis, yet I'm thinking the heat-loss incurred by the gas burner is great, and hence the least effective way to heat this water, and by a LOT.

I am grateful for how to frame the math, and then what the return would be, and then framing the answer in a meaningful, plain-english fashin.

Thanks much! Will settle a typical disagreement re: domestic energy usage.

regaards,

E. Lecht