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Alan what do you do if the family concerned might live in their home, that only has a name on it's address not a number in it's roadway??

Do you know the 12 ball oddball problem?

OKYou notice I have changed thread titleHere are three more easy problems before we try something really difficulttry these easy tests of logical thinking.Their are twelve identical featureless balls of equal volume and size. One differs minutely in mass or weight if you like.The task is to establish in three weighing steps using a very sensitive balance scale, like the scale of Libra. Which ball is different and if it is heaver or lighter. You can use any combination , three and three, four against four, anything you like but you must solve the problem in three weighs. You cant use a bathroom scale this would be useless.O O O O O O O O O O O O

Problem twoA person is rowing his bout upstream in a river flowing at three miles an hour at seven miles per hour relative, to the bank of the river. His hat falls off and only after 45 minutes does he notice this. He immediately turns around and rows at the same speed to get his beloved hat. (disregard the time taken for turning around for the purpose of this test).How long does it take for him to catch up to his hat and retrieve it??

Last problemA man sentenced to death is given a choice. He is put in a room with two PC computers, one is programed to only lie, and the other programed to only tell the truth. There are two exit doors , one leading to the death chamber and the other to freedom. He is only allowed to key in "one question" to only "one of the computers" and by this one question, he must establish the door to freedom or face execution.

3 groups of 4 balls; one group in a plate of the scale, another in the second plate; this way we identify the group with the lighter ball (if the 2 groups in the scale have the same weight, then the third group is the one we are looking for). We divide this group in two sub-groups of 2 balls and we put them on the scale, so we identify the subgroup with the lighter ball. With the last measure (one ball in each plate) we identify the single ball.

Quote3 groups of 4 balls; one group in a plate of the scale, another in the second plate; this way we identify the group with the lighter ball (if the 2 groups in the scale have the same weight, then the third group is the one we are looking for). We divide this group in two sub-groups of 2 balls and we put them on the scale, so we identify the subgroup with the lighter ball. With the last measure (one ball in each plate) we identify the single ball.How does this work if we don't know whether the odd ball is lighter or heavier?

Surely, we would need to add an extra weighing stage to work this out - ie group A is lighter than group B - this is either because there's a light ball in A or a heavy ball in B. We then need to test one against group C - If it's equal to B, the 'odd' ball is light, if it's equal to A the 'odd' ball is heavy. But that's used up one of our tests, and now we only have one left to determine which one of the 4 it could be.

Lightarrow,Respectfully you are incorrect you assumed the odd ball was lighter, it could be lighter or heavier, the problem is more complex than your solution.BenLuck must play no part in the solution it must be fool proof (no pun intended)RegardsAlan

First Weighing UUUU ——— UUUU...Left pan down One of the four balls in the left pan might be heavier (call them HHHH from now on) or one of the four balls in the right pan might be lighter (call them LLLL from now on).Proceed to Second Weighing — Case 2...Second Weighing ...Case 2 HHL ——— HLN

Where did you take that "N" ball?

QuoteWhere did you take that "N" ball?I assume from where did Get the N ball, I got it from the unweighed group of 4 balls that I knew were normal n balls. After using it I put it aside.

Just to confuse people further. Did you know it's possible to answer the question about the balls without any weighings i.e. without the scales or even in zero gravity?

Yes, basically play snooker with them and the odd one should show up.

"No it does not" If luck is not on your side your solution might require as much as 36 bouncing combinations before finding the odd ball.

Sorry it makes no sense!

2) Four dogs occupy the four corners of a square with side of length a. At the same time each dog starts walking at the same speed directly toward the dog on his left. Eventually all four dogs will converge at the center of the square. What path does each dog follow and what is the distance each dog walks until he reaches the center?

OK,How about this little puzzle.A horse is tied to a stake with a rope 5 metres in length, 10 metres in front of him is a bunch of nice hay. The hay is firmly tied down and can not be moved.The horse somehow gets to the hay and begins to eat. How does he do it?RegardsAlan

I don't know how to hide an answer, but I doubt this is the answer being looked for

The puzzle states that the hay is tied down. It does not state that the stake is driven into the ground so maybe the horse just walks over to the hay dragging the stake.(Though my first thought