Is there a method to determine the number of oxidation states for an element?

  • 3 Replies
  • 4587 Views

0 Members and 1 Guest are viewing this topic.

*

Offline siewwen168

  • First timers
  • *
  • 5
    • View Profile
Hello everyone.I wanna ask something about chemistry.[:)]

Is there a method to determine how many oxidation states that an element can exist?normally those can have more than one oxidation states is from the D-block element,such as copper(+2,+3) and titanium(+1,+2,+3,+4) and so on.[:(][:(]

I have no idea how to find out the number of oxidation states that an element can exist,for example nikel,is there anyone can help?[:D]
« Last Edit: 30/01/2009 21:16:28 by chris »
 

*

Offline Chemistry4me

  • Neilep Level Member
  • ******
  • 7709
    • View Profile
Is there a method to determine how many oxidation states that an element can exist?
No, you just have to remember them!

*

Offline lightarrow

  • Neilep Level Member
  • ******
  • 4586
    • View Profile
such as copper(+2,+3) and titanium(+1,+2,+3,+4)
No. Copper (+1,+2), Titanium (+2,+3,+4).

*

Offline Bored chemist

  • Neilep Level Member
  • ******
  • 8750
    • View Profile
IIRC Copper(III) does exist in a few obscure compounds.
BTW, why does everyone miss out zero as an oxidation state?
The elements are in a zero oxidation state (of course) but things like Ni(CO)4 (nickel carbonyl) and such have a zero oxidation state but are fairly stable compounds.
In some cases you can even get metals in negative oxidation states.

(Oh dear! I probably justr put someone off chemistry for life)
Please disregard all previous signatures.