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I think the object is to test out algorithms for computing such numbers and to demonstrate computer power

Though I too am fascinated by the trillion digits of pi so far calculated, it's more important to know HOW to calculate it. For example, this continued fraction will do nicely: 4 1^2 2^2 3^2 4^2 k^2pi = ---- ----- ----- ------ ----- ... ------- ... 1+ 3+ 5+ 7+ 9+ 2k+1+While other methods converge to pi more quickly, this is the easiest-working.

Quote from: Glenn on 16/09/2008 09:30:00Though I too am fascinated by the trillion digits of pi so far calculated, it's more important to know HOW to calculate it. For example, this continued fraction will do nicely: 4 1^2 2^2 3^2 4^2 k^2pi = ---- ----- ----- ------ ----- ... ------- ... 1+ 3+ 5+ 7+ 9+ 2k+1+While other methods converge to pi more quickly, this is the easiest-working.How does that method work? I'm no maths wizz, actually I'm mathamatically dyslexic, but its not that uncommon, 436 people out of 34 have it... mwhahahaha

So can somebody demonstrate for me how its done? How does this Infinite Series work? As I said, my maths isn't exactly out of this world... [:I] [:I]

Um... forgive me for saying this Mr. Scientist, but you are still talking in riddles. [:I] [:I]

Do you know calculus? Or would you like me to hopefully explain this in some effecient way for you to understand?

Quote from: Mr. Scientist on 31/12/2008 05:04:19Do you know calculus? Or would you like me to hopefully explain this in some effecient way for you to understand?I know a little bit of calculus [:I] If you can explain how that Infinite Series works to solve π I would be very greatful []

WOW! Must be some complicated stuff [], never mind, I can wait... the mystery of pi shall be explained. Umm... pie... [] [] [] []

Right, first contemplate what is a string or a sequence of numbers:1, 1/2, 1/3, 1/4, 1/5if we dot it at the end like so,1, 1/2, 1/3, 1/4, 1/5...It means, ''and so on,'' in this particular pattern. We can now say that the n^th number is a_n, then one can evaluate that a_1 is 1, and a_2 is 1/2, so that implies that a_n=1/n. An infinite series of numbers will look something like this:∑ = 1 + 1/2 + 1/4 + 1/8 + ... Where again, the (+ ...) means an infinite continuation of the numerical processes. Since we can't add all of infinite numbers, we can however add the first lot of ''n'' terms like∑_1 = 1 ∑_2 = 1 + 1/2 = 3/2 ∑_3 = 1 + 1/2 + 1/4 = 7/4where ∑ just means the 'sum of.'Does that help?

4 1^2 2^2 3^2 4^2 k^2pi = ---- ----- ----- ------ ----- ... ------- ... 1+ 3+ 5+ 7+ 9+ 2k+1+

Isn't it 22/7?