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So that means that if I use your factor I might get it wrong?

I can't figure this out:If total volume of seawater is 1.5 x 10(power of 21)L, and Mg found in seawater is 1.3g of Mg for every kilogram of seawater, calcute how many Liters of seawater is need to extract 8.0 x 10 (power of 4) tons of Mg?Please help me solve this problem by going step by step.Thanks.

The data given in the question is only specified to 2 significant figures. To that precision, any ton(ne) is 1000Kg, and the density of sea water is 1000Kg/M^3.

For us Americans the equivalent to 1 ton = 2000 lbs. 1 lbs (pound) = 453.6g. How can I calculate how much seawater is needed? if 1.3g of Magnesium is in a 1 kg of seawater?

So the 7.256 x 10 to10 g would be divided by 1.3g of Mg and it will give me the 5.5 x 10 to the 10th g needed of seawater?

The average density of seawater at the surface of the ocean is 1.025 g/ml [1025 Kgm^{3}] ; seawater is denser than fresh water

If total volume of seawater is 1.5 x 10(power of 21)L, and Mg found in seawater is 1.3g of Mg for every kilogram of seawater, calcite how many Liters of seawater is need to extract 8.0 x 10 (power of 4) tons of Mg?

the density of seawater which was 1.03g/mL.