I'm getting boring here

The only thing I seem to write those days is Interesting:

But that's what it is, interesting.

If I understand this right Swansont:)

You will have two beans crossing each others path?

Each beam containing around a 100,000 million protons?

And how compressed is each burst?

Or is that the total amount of particles meeting each other?

By "per bunch' I will presume to mean that they are sent in 'bursts'?

The diameter of each beam is around 64 microns which then should be 0,064 mm (0,000064 m.)

The diameter of a proton is about a Femtometer

(1 fm = 10^{-15} m = 0.000000000000001 m)

So is there any calculations done on how much of this that will represent 'space' in those collisions?

percentage, sort of

As there only is 20 collisions 'per beam crossing'?

Could one use this to measure a 'probability' - curve and perhaps get some 'measurement' of Heisenberg's uncertainty principle?

Or am I bicycling again, I know that HUP flatly states that "increasing the accuracy of measurement of one observable quantity increases the uncertainty with which another conjugate quantity may be know"

What I'm wondering though is if there would be a defined 'curve' for when you have a 'ideal' proportion of (?)variables(?) ( like proton density/time f.ex in that/those beams, and no, you're not allowed to kill the bearer:)

As a way to get more 'collisions' and of course, a probability curve for narrowing all parameters :

))