Well, this won't be too hard.

Take the constant g - this is gravitational acceleration. This is the kind of acceleration attributed to moving objects. In fact, we can pretty much tell the motion of how thing move to earth because of this constant, which has a value of about 9.8N.

x=x_0+v_0(t)+1/2(at)^2

where t is the function of time, x_0 is the initial position and v_0 is the initial velocity. Now, you can plug in pretty much any values you want for the time, position, but you can specifically replace (a) which is the acceleration symbol with [g] - ''that'' gravitational acceleration so as you might surmise to understand, force is actually attributed to the gravitational acceleration and we often give it as F=Mg - meaning that force is inversely-related to the acceleration of something, a point you where completely ignoring when i told you.

Suppose we did change the formula. It would now look like:

y=v_{0v}(t) - 1/2 (gt)^2

This means we can work out the height of an object - an the essential word here is being ''work'' - so how is work associated to everything conjectured so far?

well, this can be easier to understand. The energy of any mass is given in terms of a possible work it may do. This is the gravitational potential, and if there is a potential for any mass to move, then it SURELY CAN be said there is an associated possible work.

GPE=Wh

is the Gravitational potential energy (GPE) equation, and W is the weight and h is the height. And so:

GPE=Mgh

Where M is the mass. So i have proven here that the mass is certaily related to the work it can do. Just to prove it with a final set of equations, h/2 will be our units above the ground, so to have something move, we now yield the formula:

W_k=Fh

where W_k is the work due to kinetic energy and this work of any material body i inversely related to the force and hieght of the system from some h/2 from the earth's surface.

Done.