Oh, OK then, here's an explanation in English:

Yes, in the absence of air resistance the two objects *will* fall at exactly the same speed and hit the ground simultaneously.

There *will* be a greater force of gravitational attraction between the earth and the heavier object, but that does *not* lead to faster acceleration.

The reason can be seen by looking at Newton's equation F=ma (i.e. force = mass x acceleration).

In the case of gravity, *the force is directly proportional to the mass of the object*. So if the mass 'm' on the right hand side of the equation is doubled (say), then the force 'F' on the left hand side is also doubled. So for the equation still to balance, the acceleration 'a' must stay constant.

If you want to be even more specific (and technical) …

The rate of acceleration ‘a’ is calculated as:

a=(G*M)/(r*r)

where ‘G’ is Newton’s “gravitational constant”, ‘M’ is the mass of the earth, and ‘r’ is the distance from the falling object to the centre of the earth.

So ‘a’ does depend on ‘r’ (the distance to the centre of the earth). Of course, ‘r’ doesn’t vary significantly over most of the earth’s surface, so ‘a’ stays fairly constant at about 9.8 m/s/s. However, if you did the experiment at the top of Mount Everest (say), then you would find that the rate of acceleration is a tiny bit lower (because the distance ‘r’ is bigger when your on top of Everest).

I’d better stop there – I can sense you’re falling asleep while reading this Michael. We’ll resume the lesson tomorrow, when I’ll set you some nice problems to do as homework. [}:)]