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EquationThe gravitational escape velocity equation is: ve = √(2GM/R)where * ve is the escape velocity in kilometers/second (km/s) * G is the Universal Gravitational Constant = 6.67*10−20 km3/kg-s2 * M is the mass of the planet or sun in kilograms (kg) * R is the distance from the center of mass of the planet or sun to the center of the object in kilometers (km) * √(2GM/R) is the square root of the quantity (2GM/R) Important note: In previous Universal Gravitation Equations, G was stated in N-m2/kg2 and R in meters (m). However, it is more convenient to define escape velocity in kilometers/second (km/s). Thus, G is defined in km3/kg-s2 and R in km.

I think I found it:QuoteEquationThe gravitational escape velocity equation is: ve = √(2GM/R)where * ve is the escape velocity in kilometers/second (km/s) * G is the Universal Gravitational Constant = 6.67*10−20 km3/kg-s2 * M is the mass of the planet or sun in kilograms (kg) * R is the distance from the center of mass of the planet or sun to the center of the object in kilometers (km) * √(2GM/R) is the square root of the quantity (2GM/R) Important note: In previous Universal Gravitation Equations, G was stated in N-m2/kg2 and R in meters (m). However, it is more convenient to define escape velocity in kilometers/second (km/s). Thus, G is defined in km3/kg-s2 and R in km.So given two radii of 6371 and 6391, I get escape velocities of 11.181 km/s and 11.163 km/s, respectively.Doesn't seem to be much of an advantage to launch from a 20+ km elevation.Next I need to calculate the increase in distance for the 1-kg rocket.Thanks for listening,Agent Smith