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According to Newton 2641.9 km
if you were orbiting in a satelite you would have no sensation of weight.
According to Newton the force of gravity falls off as the square the distance of the bodies that are attracted to each other.Your origanal distance from the centre of the Earth when you are on the surface is 6378.1 Km, if you wish to reduce the attraction to half what it is at the surface you must increase this distance to square root 2 times what it was hence you must be 2641.9 Km above the surface.This attractive force will only be apparent as weight if you are supported on a solid surface if you were orbiting in a satelite you would have no sensation of weight.
Tommya300The path in which a body must move above the Earth to experience 'weightlessness' is elliptical not parabolic, in the case of an aircraft the difference is small but if you sent your satellite on a parabolic path it would disappear into space.
So assuming that you would always weigh something if standing on top of a tall tower, what would you weight at 35,786 km - the height at which Geosynchronous satellites orbit? I see a contradiction here...
Tommya300The reason for the small error in your calculation is because you take 2^.5 to be 1.414, this value is too small if you take a more nearly correct value 1.4142136 I think it will remove the error.
Quote from: Fozzie on 14/07/2010 15:59:24So assuming that you would always weigh something if standing on top of a tall tower, what would you weight at 35,786 km - the height at which Geosynchronous satellites orbit? I see a contradiction here...That does not seem too inconsistent to me. I think that says that when the tower is 35,786 km high, you weigh nothing.Does that mean that when the tower is higher than that, you have negative weight?
Geezer Yes you would float away if the top of the tower was moving at geosynchronous orbit speed!