**Model for Black Holes using the Planck Length**Three observations i made attracted my attention recently.

The first one is that many galaxies possess two black holes at their center. These black holes seems to have a relative motion to each other, similar to those observe in particle physics.

http://www.jannalevin.com/science.htmlSee "Through the wormhole", "The Riddle of black holes" episode.

The second observation is that according to the most recent computed models for a star going supernova (hypernova), the explosion is still unexplained. All models finish in the total mass going into the generated black hole.

http://iopscience.iop.org/1742-6596/180/1/012022/pdf/1742-6596_180_1_012022.pdfThe third observation is a theoretical one. According to the Holographic Principle, some kind of holographic image of everything going inside a black hole should be stored in 2D at the event horizon (for the conservation of information).

With these three observations in mind and that the elementary particle is the photon, it seems that a black hole should be a multiple wavelengths (or photons) particle. For a symmetry reason, all wavelengths should be of the same length, the Planck wavelength. In a supernova, the first black holes should appear from single particles collapsing around the center of the star. They should collapse to a particle of a size 2πR=2πLp=ʎp (for a circle approximation). If all photons collapse into a single particle of this size, there will be no explosion, only an implosion and nothing will be left. The photons (or any way you want to call it) collapsing will connect into a ring that , when enlarging, will cause the explosion of the supernova.

The Planck Length = 1.616 x 10-35 m

ʎp = 2πLp = 1.0154 x 10^-34

http://math.ucr.edu/home/baez/planck/node2.htmlSupposing the quantization is based on a minimal wavelength λp = 2πL

p.

A circular black hole having a circumference of N*ʎp and a mass m, will have an energy of

E = mC2 = N * h * C / ʎp

For N = 1,

m = Mp = 2.1916 x 10^-8 kg (Planck mass)

R = N * ʎp / 2π

Where N = m / Mp

R =(m/Mp) * (ʎp / 2π)

R = m * 7.374 x 10^-28

For a one solar mass black hole,

R = 1466.6 m, in comparison, the Schwarszchild radius is twice as large at about 2951 m.

For the black hole at the center of the Milky Way, evaluated to approximately 4 million solar masses,

R = 5.867 * 10^9 m or a diameter of 1.173 x 10^7 km.

Again in comparison, the Schwarszchild radius is about 1.18 x 10^7 km, twice as large.

For a sphere made with this kind of rotating wave at a speed of C, the simplest solution is

R(sphere) = R (circle) / √2

For a diameter of about 0.929 x 10^7 km

Validation:

At the event horizon, all particles are transferred into light and travel at the speed of light. At the speed of light, there is no relativity. Once a photon has reach the event horizon, there is no relative movement... Before and after, equations must have a continuity... Relativistic energy due to gravity is perpendicular to the ring and it is reciprocal for both the particles and blackhole, so it just vanishes... (in gamma ray burst)

F = GM1M2/R^2 = M2 * a

Where

G is the Gravitational constant

M1 is the black hole mass

M2 is the mass of the particle

R is the radius of the event horizon or the size of the black hole

a is the radial acceleration of the particle as a photon rotating at the event horizon and is equal to v^2/R = C^2/R.

=> GM1/R^2 = C^2/R

=> G/C^2 = R/M1

R = GM1/C^2 (or half the traditional Schwarszchild radius)

Thus a prediction of maximum event horizons sizes of half the sizes of the Schwarszchild radius.

The black ring is made of two concentric rings separated by the Planck length. The rings are made of multiple photons, each having two wavelengths of 2pi*L

_{p}, one wavelength inside and one outside. There is no gravity in the middle.

If the Big Bang was the breaking of a black hole, the space in the middle of the ring(s) would look like a faster than light expansion from the point of view of the actual Big Bang Theory...