0 Members and 1 Guest are viewing this topic.
Ok, I'll buy that.If we think of a two ball cradle, with the second ball fixed, then the first ball would be deccelerating (exponentiall?) as it approached the opposing magnetic field - is that correct? - and presumably would accelerate at the same rate if the poles of the fixed ball were reversed to give attraction? If the clamped ball was released at the exact moment of contact then how far would the two balls swing? Would the kinetic energy within the combined pair be equal to the kinetic energy of the lone ball at the moment of impact or what?This has raised another thought in my mind - if one is over the North magnetic pole of the earth and drop a bar magnet north pole downwards, at what point in its fall will it flip - is it fixed or dependent upon the velovity of the falling magnet? - e.g. if dropped from a great height it would be moving faster than if from shoulder height so would, flip closer to the earth's surface?Oh, the burden of an enquiring mind on others...
Here is a link to some interesting simulations but no magneized Newtons cradle as yet.Goto it programmers
But wouldn't we have to rename it "Newton's woody?"
I don't see why it would matter if you used magnets or not (except that they might spin round and stick to eachother).
Duncan Amos asked the Naked Scientists: Hi Would a "Newton's Cradle" perform correctly if the balls were spherical magnets held apart by magnetic repulsion? i.e. view from the front - a five-ball cradle would have the spheres lined up as N-S, S-N, N-S, S-N, N-S and the pivot points of the arcs of swing are aligned above the neutral points so that everything is at rest. It might be that the falling ball would need to be outside the set in the rest state as it's removal might influence the rest state of the others, or not? Hoping you can help calm an old man's puzzled brain! Duncan AmosWhat do you think?
Duncan - you're right OP=Original Post/Poster General Question - do we have an h bar we can use?