Looking at this explanation.

Gravitational potential. I get a distinct feeling of a 'force', which I don't particularly like myself.

as i look at gravity as a property of SpaceTime.

Here is another way of describing it.

"In the case of motion-induced Fitzgerald contraction, the effect is, as

I said, arguably a "trick of the light" (but it seems pretty real to me,

at least in some cases). Space itself is notably not affected; only the

measurements seem to change.

In the case of a gravity well, space itself is unambiguously distorted.

The metric tensor changes, and to deal with this you need to dive into

general relativity and pseudo Riemannian geometry. To deal with the

gravitational field around a planet, you can look at the Schwarzschild

metric (Wiki has a page on it, for example), which will give you some

feel for how the distortion "looks".

But there is a very important point here, which is that there are

several kinds of distortion, and they can happen together or separately.

-- The "curvature" is nonzero in the presence of a gravitational field

which has tidal effects. This results when there are nonzero second

derivatives of the components of the metric tensor. Nearly all real

gravitational fields have tidal effects. The Schwarzschild metric, for

instance, is curved.

-- The "connection" is nonzero when there's a gravitational gradient --

i.e., when there's a direction things fall in. This is a result of

nonzero values for the the first derivatives of the components of the

metric tensor. This is associated with distortion along one axis, I

think, and is somewhat analogous to Fitzgerald contraction. However,

note well this this has very little to do with time dilation!

-- Finally, there's gravitational time dilation, which is correlated

with the gravitational *potential*, *not* with the local gravitational

field strength!

For example, if we dig a spherical chamber in the center of a planet,

there will be *no* gravitational "field" within that chamber caused by

the mass of the planet. However, the gravitational potential is lower

in that chamber than it is on the surface, and clocks in the chamber

will run SLOWER than clocks on the surface.

As another example, if we dig a spherical chamber OFF CENTER inside a

*uniformly* *dense* planet, the gravitational field within that chamber

caused by the mass of the planet will be almost exactly uniform. In

other words, there will be no tidal effects, and it will be impossible

for an observer within the chamber to determine whether he's being

subjected to a gravitational field, or is simply accelerating at a

uniform rate. Clocks will runs slower at the "bottom" of the chamber

than at the "top". "

But what does it say?

that gravity is a 'force'?

If gravity's potential is called a 'force' then I have a hard time excluding that from 'gravity'?