The power generation calculation depends on the depth and the size of the pipe.

Alas, it does not. To generate power you need to do work, and the only thing that's doing any work is the tide elevating the pontoon against the force exerted by the cable. It's quite simple to determine how much work the tide does, or the power, which is the rate of doing work. I calculated that in my previous posts.

You can do anything you like with systems of gears and cables, but you will never be able to use them to multiply the amount of work done by the tide acting on the pontoon. The second law of thermodynamics has yet to be broken.

I offered to review your calculations or show you the calculations I've used. You've chosen a third option. Unfortunately, your way takes the debate no further forward and denies us a learning opportunity, where either you learn something new or I do.

However, strongly you assert something it means nothing without proof!

Apparently you didn't like my calculations [

]

OK, here we go again, from the top!

To generate power something has to do work. We are trying to derive power from tidal energy, so it must be the tide that's doing the work - so far so good, (I hope).

According to Wikipedia (Work) - "The SI unit of work is the joule (J), which is defined as the work done by a force of one newton acting over a distance of one meter."

In this case it's the vertical pull on the cable caused by the pontoon rising in the tide that is doing all the work (if you don't believe me, please tell me what other source of energy you are tapping into.)

So, if we know how far the pontoon was raised by the tide and the force exerted by the cable, we can multiply one by the other to determine the amount of work done (in joules).

The force in the cable equals the force produced by the buoyancy of the pontoon acting against gravity, which is 9.81 times the mass of water displaced - (don't blame me, blame Archimedes.)

If the pontoon displaces 400,000t or 400,000,000kg (which it must in order to submerge a 67,000 cubic meter storage vessel with a 6:1 mechanical ratio) the force in the cable is 9.81 times 400,000,000 = 3,924,000,000N. (Could be quite a thick cable!)

We know the tide lifts the pontoon 2 meters twice a day, or 4 meters in 24 hours.

Therefore, the work done per day (force times distance) is 9.81 x 400,000,000 x 4 = 15,700 MJ (megajoules)

The average work done in one second must be that value divided by 86,400.

Therefore, average work per second is 15,700,000,000/86,400 = 182,000 J/s = 182kJ/s

A watt is a rate of doing work at 1 J/s (joules per second), so the average power is 182kW. It looks to me that you are assuming continuous generation in your calculations, in which case you better be using average power, not peak power.

BTW, 1 megawatt-hour equals 3,600 MJ (megajoules), so 15,700 MJ per day can generate a maximum of 4.36 MWh per day.