i figured it out

i figured it all out

and it is the weirdest type of thing ive ever seen

i had to invent a new operation, i use ~ to represent it.

It basically is to c as - is to b

basically anything ~ X = anything + (c1 * X)

but what happens when its a negitive?

whats c1 * b1 equal

at first i thought it equaled b1, then c1, then a1...

it equals all three

the axiom of normal math, that a number equals only one number, is thrown out...

assuming that c1 * c1 = b1 (which i might have to revise to get rid of this, cause i dont feel comfortable accepting that its true now)

a1 + b1 + c1 = 0 also means c1^4 + c1^2 + c1 = 0

which means, when you divide by c1 a various number of times

you get that

c1^4 + c1^3 + c1 = 0

c1^3 + c1^2 + c1 = 0

c1^4 + c1^3 + c1^2 = 0

this would lead to the conclusion that c1^3 = c1^4, c1^2, and c1

which in turn makes a1 = b1 = c1

which means that a1 + a1 + a1 = 0

which makes a3 = 0

a1 = x

add 0 to boths sides, or a3

a4 = x + a4

this gives you that X also equals 0

so a1 = 0

basically all numbers equal 0 (assuming tha bc1 can be a1, b1 or c1)

so basically c1 *b1 and c1/b1 and b1/c1 or any equation containing a bc1 results in it being undefined...

unless you choose 1 amount fo bc1 and keep it that your whole time...

this would give multiple answers for each problem

like 2a + b1 = X

~b1 -b1 (on both sides) -this step spawns multiple solutiuons, depending on waht you set ~b1 as equal to-

a2 = x ~ b1 - b1

a2 = x + c1(or b1 or a1) + a1

-a2 ~a2 (on both sides)

0 = X + c1(or b1 or a1) + a1 - a2 ~ a2

0 = X + c1(or b1 or a1) + a1 + b2 + c(or b1 or a1)2

this is where its easier to solve, since you just needa put things in to get it to equal c(Y) + b(y) + a(y) = 0

you choose one of the options, choose c1 first

0 = X + c1 + a1 + b2 + c2

0 = X + c3 + a1 + b2

here the solution would be X = -c2 - b1 this becomes (b or c or a)2 + a

so its b2 + a, c2 + a, a3

then you go back and you choose a different sign (chose B)

and repeat the rest

(keep in mind its alte imr eally tired so that is probbably all illogical)