I searched around google for this and I got the answer that: Since P=I^2*R, so high-voltage and low current would result in less power losses.

What confuses me is that P=I^2*R can also be written as P=V^2/R; which tells a different story. According to this equation, the lower the voltage, the lower the power losses. In fact, this second equations seems to suggest that transmission at lower voltages should be more efficient, since the factor V is being divided by R, whereas in the previous equation I was being multiplied by the same factor..

So, yeah, I'm confused.