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Why is a photon not considered to also be a monopole?

A photon consists of an ...sorry, you cannot view external links. To see them, please REGISTER or LOGIN.

I venture to suggest that both statements are true:Maxwell's differential equations for the electromagnetic wave apply on all scales, down to zero field strength.

At the lowest possible field strength (as represented by an isolated photon), Maxwell's equations still apply, so a photon consists of an electromagnetic wave.

Alan, a monopole doesn't have to be signed. You can have a gravitational monopole, which would be a point of mass.But a monopole represents the distribution of a field coming off a point source, much as gravity comes off a point mass or electric field comes off a stationary point charge. This field is by definition spherically symmetric. For a photon to be a "monopole" it would have to emit a spherically symmetric field, which it doesn't. For it to be a monopole field, it would have to look like the static field coming off an electric charge, which it also doesn't.

There is, in fact, non-classical light which cannot be described in terms of classical (Maxwell's) equations

Quote from: JPThere is, in fact, non-classical light which cannot be described in terms of classical (Maxwell's) equationsOk, now I understand that there is such a thing as non-classical light.Question: Would one isolated classical photon obey Maxwell's equations?