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It appears from your remark that (T' = T) means .........

Quote from: HeyBert on 19/02/2015 04:10:36My calculations, where γ = (1-v^2/c^2)^-1/2;When the race occurs within the stationary laboratory frame (v = 0), no calculation is needed (inverse Lorentz transformation reduces to Galilean format) and the ratio of the photon time span to the electron time span WRT the stationary laboratory frame is simply;Photon: τ = τ'Electron: t = t'You keep posting things like this without defining them. What you said tells us nothing about what those quantities are/mean.

My calculations, where γ = (1-v^2/c^2)^-1/2;When the race occurs within the stationary laboratory frame (v = 0), no calculation is needed (inverse Lorentz transformation reduces to Galilean format) and the ratio of the photon time span to the electron time span WRT the stationary laboratory frame is simply;Photon: τ = τ'Electron: t = t'

It appears from your remark that (T' = T) means that you are assuming I am discussing what K measures in their own frame vs what K' measures in their own frame.

When you apply transforms to K' I have to assume you are working from the viewpoint of an observer in K, with a clock in K, observing events in K'.

It is obvious that my original presentations suffer many flaws due to the wording and the related mathematical results as a result of this wording.

...... What if I strip out all the extraneous referencing to observers, rest frames, etc.?

PART 1 (One-Way Events)WRT Einstein’s book (Relativity: The Special and General Theory), Part 1, Chapter 11 gives the Lorentz transformation (LT) as;

First off I've asked you several times what "There are two parallel linear events (A and B) with uniform velocity along the positive x-axis." means and I've yet to get a response. You didn't even state what the worldlines are which are supposed to be parallel. I'm going to assume that you're referring to the following worldlines;Worldline A: Worldline connecting origin with event AWorldline B: Worldline connecting origin with event BWorldline A is the worldline of a photon which is emitted from the origin and moves in the +x-direction and ends up at event A. That means that it's a line which is 45 degrees with respect to the +x-axis (and of course its also a line which is 45 degrees with the ct-axis).Worldline B is the worldline of a particle which moves at a speed less than the speed of light and ends up at event B. That means that it's a line which is greater than 45 degrees with respect to the +x-axis.This means that it is a line which is 45 degrees with respect to the +x-axis (and of course it’s also a line which is 45 degrees with the ct-axis).Therefore it follows that these two worldlines are not parallel. So what in the world do you mean by “parallel events”?

It is obvious that my original presentations suffer many flaws due to the wording and the related mathematical results as a result of this wording. What if I strip out all the extraneous referencing to observers, rest frames, etc.?

PART 1 (One-Way Events)WRT Einstein’s book (Relativity: The Special and General Theory), Part 1, Chapter 11 gives the Lorentz transformation (LT) as;t’ = (t-vx/c^2)γ, where γ = (1-v^2/c^2)^-1/2Referencing Einstein’s book (Part 1, Chapter 11), we merely apply the transformation to two events (i.e. moving electrons) in K from (x = 0) to (x) in unequal times (τ) and (t).WRT K’: τ’ = (τ-vx/c^2)γ t’ = (t-vx/c^2)γEvaluating the ratio of these times at (v) gives the results WRT K’ as;* τ’/t’ = (τ-vx/c^2)/(t-vx/c^2)Evaluating this ratio at (v = 0) gives the results WRT K as; τ’/t’ = (τ-0*x/c^2)/(t-0*x/c^2)* τ’/t’ = τ/tPART 2 (Round-Trip Events)Referencing Einstein’s book (Part 1, Chapter 11), we merely apply the transformation to two events (i.e. moving electrons) in K from (x = 0) to (x) in unequal times (ϖ) and (T), then from (x) to (x = 0) in these same times (ϖ) and (T).WRT K’: 2ϖ’ = (ϖ-vx/c^2)γ + (ϖ+vx/c^2)γ 2ϖ’ = ϖγ-(vx/c^2)γ+ϖγ+(vx/c^2)γ* 2ϖ’ = 2ϖγ 2T’ = (T-vx/c^2)γ + (T+vx/c^2)γ 2T’ = Tγ-(vx/c^2)γ+Tγ+(vx/c^2)γ* 2T’ = 2TγEvaluating the ratio of these times at either (v or v = 0) gives the results WRT to K’ or K as;* ϖ’/T' = ϖ/T

And what law states I have to answer your questions anyways?

Quote from: HeyBertIt appears from your remark that (T' = T) ...To whom are you speaking to? I don't see Colin making any such comment.Quote from: HeyBert...means that you are assuming I am discussing what K measures in their own frame vs what K' measures in their own frame. This was not at all what I was discussing.That is exactly what it appears that you're discussing. If it isn't then your posts are extremely deceptive. When someone places a prime on a variable it means that the quantity that has the prime on it is measured in the primed frame and vice versa. I.e. A' is measured in frame K', B is measured in frame K, etc.

It appears from your remark that (T' = T) ...

...means that you are assuming I am discussing what K measures in their own frame vs what K' measures in their own frame. This was not at all what I was discussing.

Working things out on another forum right now. Learned to frame the problem in a "relativity friendly" format from another user and have good positive communication going. Thanks for the offer though, and I'll let you know If I come back to this or identify where my logic went astray.

Yeah. I know. I saw that and I saw that you're making mistakes there too. I've already shown you how to do this right so what's your objection to it?

His problem is that he wants his idea to be correct, not get the physics correct.

Quote from: PmbPhy on 23/02/2015 15:28:25His problem is that he wants his idea to be correct, not get the physics correct.Ah, so there is an agenda, I just couldn't put my finger on it.He calls it a maths problem, but to me it seems like bad methodology.I'll put the beer on ice.

Colin - You never answered me. I sent you a PM asking you a question. What is your response?

Colin2B + PmbPhy,It's a hobby...It's a math problem...even if I'm wrong, it's fun to me...stop being so offensive and judgmental! You're both acting like a couple drama queens on here.

Posts #48-#49. And don't bother "explaining", not interested.

In the 'New Theories' section of "Got a new theory on something? Post your hypotheses here..."This is where you choose defend the pillars of science? Your actions do nothing but make people afraid to freely discuss their ideas on this forum. Great job Ace!

Here is my new theory which shows that relativity is wrong. If it's wrong then keep it to yourself because I don't care. If what I'm writing is confusing then please don't ask me to clarify. etc.