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no one really knows why a particular atom decays !!
Can someone tell me what controls the instability in atoms of certain isotopes? Is the activity internal or externally stimulate For?I have a watch made by luminex which had a tritium activator of the zinc sulphide and which gives me as much light as I need to read at nightThe light will reduce as the half life of 11 year ish of tritium decays.Something causes the unstable activity in a constant unchanging rate. WHAT?
Fascinated to see that no one really knows why a particular atom decays !!
Can someone tell me what controls the instability in atoms of certain isotopes?
a nucleus with too many neutrons will be unstable
One way of looking at the energy of the nucleus is to view it as having ...sorry, you cannot view external links. To see them, please
REGISTER or LOGIN. When you fill one shell, you start filling the next shell. The protons have one set of shells, and the neutrons have their own set of shells.When you have too many neutrons in the atom, they start to fill higher shells while leaving lower proton shells empty. You can actually release energy by expelling an electron=beta particle (and a neutrino), converting a neutron into a proton, which can then fall into a lower shell, releasing energy in the form of a gamma ray.
Why are you so concerned about energy when this is about stability?
Quote from: PmbPhyWhy are you so concerned about energy when this is about stability?If the proton & neutron shells are full to a similar extent, then it takes energy to convert of neutron to a proton. Since these large quantities of energy are not readily available within the nucleus, the nucleus will be stable.To a large extent, the stability of an atom is determined by Energy considerations:If a nucleus is in the lowest energy state, and all surrounding states have a higher energy, that nucleus will be stable.If there is an adjacent, reachable state with a lower energy, the atom is likely to decay into that state, at a rate determined by the energy in the environment, and the size of the quantum well blocking the transition.