Momentum is derived by the equation p = mv, where p is the momentum, m is the mass and v its velocity. Since the maximum velocity of anything in the universe is c then the potential maximum momentum is p = mc. If we then integrate this we find that

m[tex]\int \frac{1}{2} c^2\, dc[/tex] + C

equates to kinetic energy. In this case equaling (1/2)mc^2 + C. This is understandable since the potential maximum kinetic energy for the mass has been derived from the potential maximum momentum. If we disregard C then the kinetic energy is half the total mass energy.

Kinetic energy is in its proper form as ke = (1/2)mv^2. If we then say e = mv^2 what would this mean?

EDIT: corrected to "If we disregard C then the kinetic energy is half the total mass energy."