of cause you can not see the values in reality,

player 1 or player 2 has the better chance of picking an (n)?

Yes, the way you have 'rigged' it, player 2 has a better chance.

But you have given y 6 times what would occur from a random distribution and as you play more and more games the sequence tends towards a random distribution.

Also, the way the decks are shuffled you will tend to get 4/52 in the y direction as well as x, so in the long run ( which is what probability is all about) you will get the same result.

PS, I think you know, but I forgot to say that probability is often shown as % ie 1=100%=certainty etc

Have fun with your new theory

x axis 1-52

y axis ?

52²

1-52 is randomly shuffled along the x axis. When the shuffle ends, the unknown sequence is set of each variant in position within the square,

the y axis contains 1-52 variants in rows where the x axis contains columns of unknown values

stupid me , I had it back to front, sort of.

It does not matter if I un-rig it becuase x is not equal to y

x

x

x

x

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x

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x

x

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x

we know the vertical or Y axis as repeat values over a large quantity.

lets do this properly 52²

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....................................................<52 playersWhat is the chance of x axis shuffling randomly its 52 variants of each row and aligning 1-52 to each players column?