0 Members and 1 Guest are viewing this topic.
If I was to apply a force on the northerly point of a stationary basket ball , creating pressure that contorts the shape of the basketball into an obloid, and fixed this pressure to be set, then I glazed the surface of the ball with icing, and let the icing set, what will happen to the icing when I remove the fixed force?
Would this be the correct algebra explanation?[attachment=20014]ΔF[y]/t=Δ[dy]=ΔF/t= Δ[dx]=[dy]>[dy]=[dx]<[dx]□
Quote from: Thebox on 24/09/2015 02:18:38Would this be the correct algebra explanation?[attachment=20014]ΔF[y]/t=Δ[dy]=ΔF/t= Δ[dx]=[dy]>[dy]=[dx]<[dx]□ Reasonable first try, but some thoughts:F[y1]= -F[y2] because these have to be equal and opposite.Any force in the x direction would also need to be equal and opposite, but if you are talking about applied force, then in your example this would be 0.I don't understand what you are trying to say with g+av, use words.Also, what is r? Usually it stands for radius, but a force cannot = a distance. This is the equivalent in English of saying that cat=rock, makes no sense.Neither does this ΔF[y]/t=Δ[dy]=ΔF/t= Δ[dx]=[dy]>[dy]=[dx]<[dx].You have to try to make sense otherwise people will stop responding to you. Notice how they do it with others who make silly statements, they are not being sent to Coventry, it just becomes more effort than it's worth. The only reason some of us persist with you is that we believe you have made real progress, please don't regress.