Do we account for acceleration in Gravitational time dilation?

  • 0 Replies
  • 448 Views

0 Members and 1 Guest are viewing this topic.

*

Offline Thebox

  • Neilep Level Member
  • ******
  • 3214
    • View Profile
Object (A) at ground state has zero velocity v=0.

object (A) at ground state has 9.82m/s of acceleration always, this is true or we would have no weight.


1 second of the Caesium clock is equal to ground state is equal to the weight and acceleration,


a golden constant ratio.



Do we account for this?

φ=(1 second = 9,192, 631,770 cycles of the standard Cs-133 transition=a9.82m/s=(F=ma)=Newtons)

Δφ=σ(1 second = 9,192, 631,770 cycles of the standard Cs-133 transition=a9.82m/s=(F=ma)=Newtons)



Clock (a)   at ground state on earth

clock (b)  at ground state on a sister earth 1000000 Ly away


M1=M2 in every detail including rotational speed and mass


Clock (a) is always in the present


clock  (b) is always in the present

X1
X2
y'=σ
t'=σφ

« Last Edit: 30/11/2015 13:09:18 by Thebox »