Object (A) at ground state has zero velocity v=0.

object (A) at ground state has 9.82m/s of acceleration always, this is true or we would have no weight.

1 second of the Caesium clock is equal to ground state is equal to the weight and acceleration,

a golden constant ratio.

Do we account for this?

φ=(1 second = 9,192, 631,770 cycles of the standard Cs-133 transition=a9.82m/s=(F=ma)=Newtons)

Δφ=σ²(1 second = 9,192, 631,770 cycles of the standard Cs-133 transition=a9.82m/s=(F=ma)=Newtons)

Clock (a) at ground state on earth

clock (b) at ground state on a sister earth 1000000 Ly away

M1=M2 in every detail including rotational speed and mass

Clock (a) is always in the present

clock (b) is always in the present

X_{1}=φ

X_{2}=φ

y'=σ²

t'=σ²φ