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I don't understand why the double bond marked on the picture doesn't give 2 more stereoisomers
What about the double bonds in the cyclic structures?
Ah, i understand it now.Correct me if my understanding is wrong.The bond i marked has a carbon with two methyl groups, so it can't occur as stereoisomers.The double bonds in the cyclic structures can only occur in that one configuration for the loop to be complete.Therefore the only two isomers of the compound come from the chiral centre.
That is correct. R1 R2 \ /The C=C structures can only lead to different isomers if R1 ≠ R3 AND R2 ≠ R4. / \ R3 R4Additionally, if R1 and R2 (or R3 and R4) are connected in a ring that contains fewer than 8 consecutive bonds, there is only one stereoisomer that is physically possible (R1 and R4 cannot be connected in a small ring).