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You're right, english is not my first language, but all forums in physics ban new theories. I found only this forum. And forums where people believe it is possible to create over-unity devices are more interesting with videos (fakes) than physics. If you don't understand something I can explain with others words and phrases, the device is not complex.
I consider the mass at 0 like the friction, if you want you can consider the mass very small. The potential energy at start comes from the springs, even the mass of the spring is small the kinetic energy exist.
To believe or not to believe ? some people believe in god (I see your personal message about Jesus) I believe it is possible to create the energy and it is not exclusive, people can believe 2 beliefs
http://imgur.com/VuLGDBphttp://imgur.com/itT8yiwhttp://imgur.com/EMrJDu4I forgot the final energy at 2 first cases: read "the final energy is Y" for the first case and "the final energy is Y-d" for the second:http://imgur.com/YPCKHau
With an external device, I didn't draw it. But the I count the energy needed for move in the spheres and the energy recovered to move out the spheres. The volume is always the same.
Yes, this is a cycle. At start there is a potential energy Ep1, at final the potential energy is Ep2, the walls recover the energy Ep1-Ep2. Ep2<Ep1. The energy from the difference of lengths L1/L2 is an additional energy that I don't find where I lost it.
Like the mass of the blue spheres is near 0, I think the sum of forces from the blue spheres on the white disk is 0. The white disk don't have a force and like its mass is near 0 I don't need an energy to move it (in theory). I move in/out the blue spheres in the same time:
I move out the blue spheres in the same time I move in the others. For that, I need, at start, an extra layer of blue spheres with springs to move in because I can't move out and move in the same spheres in two different places. There is always a layer of blue spheres outside the device. The last layer of blue spheres moving out becomes the layer outside, ready to be used for another move-in/out. Like that the pressure don't change because I move in/out the blue spheres.
I study the sum of energy only from the left position to the right position.
I don't repeat the cycle.
Yes, I count all the energies stored in the springs.
I supposed the force from each spring don't change with the length of the spring, just to simplify the thinking of the device. So at start the force from a spring is F and at final the force of a spring is F. It is theoretical device but just because like that it is easier to resolve or to find the error.
The energy is well stored in the springs at start. With a standard spring, the force is k*x but here I use the equation F=k. Some springs exist:http://www.scherdel.com/en/produkte/umformtechnik-technische-federn/roll-triebfedern/index.phpIt is possible to think with the force = k to simplify the device.
I do. My thinking:1/ At start, the energy is 'X-d' with 'X' the energy stored if the container was fulled of blue spheres, and 'd' the energy lost because there is the white disk
2/ The walls give W
3/ At final, the energy stored is Y-d with 'Y-d' the energy stored in the container and W+Y-d=X-d The term 'd' is canceled because it is at final and at start
BECAUSE the white disk rotates.
I But I win the energy from the move out/in the blue spheres.
I would like to say if there was not the white disk, the energy stored inside the container is X.
An external device give the energy to rotate the right wall and recover the energy from the left wall.
The energy stored in the device is the sum of the lengths of the springs, not the number of springs. Like the white disk rotates, the energy lost at start (compared with a container fulled of blue spheres) because there is the white disk is the same that at final because it is a rotation.
The rotation of the white disk ? You would like to rotate the walls (change the shape of the container) but not the white disk ?
X=Y+W (without the white disk)Like X=Y+W even there is the white disk
in the first case or the second case, the potential energy stored in the container pass from X to Y (Y<W) but the external device recovers from the walls the energy: W=X-Y. But in the first case, I win the potential energy : sum of difference of length (L1-L2) of all the springs I need to move out/in. In the second case, I lost the potential energy : sum of difference of length (L2-L1) of all the springs I need to move out/in.
Ok, the white disk rotates. I'm not sure to understand, Maybe we are agree on that point. When the white disk is in the container, the container has less stored energy because there are less springs. But like the white disk rotates, the energy in less at start is the same that at final.
I have the same variable 'd' at left and at right in the equation (start and final) so I can cancel 'd':X-d=Y-d+W <=> X=Y+W
But delete a variable don't say the variable don't exist at all.
The representation of the energy at start is X-d, at final it is Y-d+W + the energy from the differences of length L2/L1. If the energy at final was only Y-d+W the energy will be conserved but I recover the energy from the differences of lengths L2/L1 of the blue spheres I move out/in.
But it was lower at start too.
The presence of the white disk inside the container affects the stored energy. Because the stored energy is the sum of all lengths of the springs. And if there is the white disk, there are less springs, so the sum is lower. But like the white disk rotates, the stored energy is reduced at start of a value I noted 'd' and at final it is 'd' too. If the white disk is fixed, the stored energy is changed, from start to final, because the orientations of the springs change, at start the orientation is 45° at final it is 90°, the mean lengths pass from sqrt(2) to 1 (for example).
Ok, forget the sign "<=>' in my previous message. I calculated the energy without the white disk. Without the white disk, the energy at start is for example 100 not 95. And I know the energy at final too without the white disk. I calculated the energy recovers by the walls, that energy don't change if the white disk is inside the container or not. When I added the white disk, I know I lost for example '5'. The values of the variables W, Y, X and d are known.
But in this case, I don't understand where I remove that energy from the container, do you ?
I recover the energy from the difference of lengths L2/L1, maybe that energy come from the the stored energy inside the container but in this case I would like to understand how the energy is transfered.
The springs attract (want to reduce their length), so when the spring reduces its length it gives an energy. For me, to have the conservation of the energy, the springs that move out/in musn't give or take any energy. The equation of conservation is X-d=Y-d+W, with X=Y+W.
The action of move out the blue spheres gives the same energy than the action of move in (I don't speak about the length of the springs) because the pressure is the same at left than at right for each layer.
When I count the energy, the device is not only the container, it is the external device that rotates the walls, it is the device that changes the length of springs from L1 to L2 (that device recover an energy). All the things I speak are the closed device, so the sum of energy must be constant.
I supposed the springs perfect, mass very low, no friction, etc. But even you considered a real spring, the energy lost in friction is an energy, that energy from friction must be take in the account of the sum.
I don't understand how ? I have all the energies: X, W, Y, d, and the equation with the conservation of the energy: X-d=Y-d+W (the left member is the energy at start and the right member is the energy at final). But I have X-d=Y-d+W+e with 'e' the energy that comes from the difference of the length L1/L2.