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Why does a flywheel fly apart? From a mechanical engineering viewpoint you can calculate all the forces within a flywheel and determine how fast it can spin based upon the bonding forces. Thus each grinding wheel has different speed ratings in rpm. That is standard. Once we have super strong solid metal or space age carbon fibers, we can achieve very high rotations. Let us assume that we can produce a flywheel that can withstand extremely high velocities. What will make it fly apart? We are now left with Einsteinian space time type problems. We are also left with Doppler corrections to these problems. Linear space time has Doppler corrections and the same would be true orbital systems. The high velocity flywheel from a linear perspective would have a lower orbital velocity near the center and a larger velocity near the surface. Even without the Doppler effects, the center of the wheel will shrink but the outside of the wheel will shrink even more in the direction of rotation. We then get Einsteinian type forces which press the outer surface closer together and force the entire package to shrink slightly in radius. This causes the flywheel to crack on the outer surface and fly apart. Thus even the best flywheel will be destroyed long before we reach near the speed of light C. The Doppler effects when added to Einstein’s regular equations make the situation worse but it is sufficient to see that a variation of special relativity is applicable to a spinning wheel. What do you guys think?

determine how fast it can spin based upon the bonding forces

Once we have super strong solid metal or space age carbon fibers, we can achieve very high rotations

We then get Einsteinian type forces which press the outer surface closer together and force the entire package to shrink slightly in radius. This causes the flywheel to crack on the outer surface and fly apart. Thus even the best flywheel will be destroyed long before we reach near the speed of light C. The Doppler effects when added to Einstein’s regular equations make the situation worse but it is sufficient to see that a variation of special relativity is applicable to a spinning wheel. What do you guys think?

Particles approaching a black hole at a tangent will accelerate to near-c before diving into the event horizon, so there's plenty of stuff out there doing relativistic things where gravity is a lot stronger than any chemical bond.

Quote from: alancalverd on 17/08/2016 17:48:13Particles approaching a black hole at a tangent will accelerate to near-c before diving into the event horizon, so there's plenty of stuff out there doing relativistic things where gravity is a lot stronger than any chemical bond.Agreed. If that's what Jerry meant then I'm ok with it, but I still don't understand the Doppler reference.

Quote from: Colin2B on 17/08/2016 17:58:34Quote from: alancalverd on 17/08/2016 17:48:13Particles approaching a black hole at a tangent will accelerate to near-c before diving into the event horizon, so there's plenty of stuff out there doing relativistic things where gravity is a lot stronger than any chemical bond.Agreed. If that's what Jerry meant then I'm ok with it, but I still don't understand the Doppler reference.I suspect Jerry is referring to Lorentz contraction instead.