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BTW - I described the GR cause (of accelerated motion) in Reply #338.

Zero velocity is a perfectly valid initial state. That's how Newton's apple got started for example. Newton makes no hypothesis about how the force of gravity gets things moving. The GR view is that a stationary object moves through time at light speed and acceleration simply rotates the velocity vector into the spatial domain. It's a change of heading in the spacetime continuum.In my simplified scenario, the traveller is in free fall and the bystander is accelerating. That change eliminates the need for variable thrust, which is a significant complication.Variable light speed is one possible interpretation of GR. Some people prefer to think of it as spacetime dilation, akin to SR. In either case, we have eliminated the effect by placing the observers at the same altitude at some instant of time.If mass, space and light speed are invariant then higher energy (potential or kinetic) equates to shorter seconds.Anyway, that's the picture painted by GR. The question is, what does it look like in your theory?

Quote from: timey on 21/03/2017 14:21:50and where the value of p changes for already emitted light (in the gravitational field*) in relation to the h constant, this extra or lesser length in the wavelength isn't distance related anymore,Your obsession with h is worrying. p doesn't change "in relation to h". p changes because the photon's kinetic energy changes as it travels through a gravitational field gradient. The value of h is irrelevant to the fractional change in p, E, L or f, which are all related through c and given by the same equation (or its inverse, obviously).

and where the value of p changes for already emitted light (in the gravitational field*) in relation to the h constant, this extra or lesser length in the wavelength isn't distance related anymore,

Yes - that's right, p doesn't change in relation to h, but wavelength changes in relation to p in relation to h.p is changing in relation to v, and v is changing in relation to a, where a is either increasing or decreasing due to a potential energy to kinetic energy conversion, (where relativistic mass in relation to kinetic energy for light in current physics remit ensures 0 acceleration/deceleration), but it is indeed p in relation to h that denotes the change in the wavelength...

v doesn't change. We're talking about photons.

Which is why I said:Quotewhere a is either increasing or decreasing due to a potential energy to kinetic energy conversion...for mass accelerated or decelerated in the gravity potential.... And added this:Quote(where relativistic mass in relation to kinetic energy for light in current physics remit ensures 0 acceleration/deceleration)For light in the gravity potential..In either case:Wavelength = h/pwherep = mvor p = h*vbarwherevbar = v/aAnd I am looking at acceleration in the gravity potential being 3rd time dilation related, where I am also looking at GR time dilation being potential energy related, and considering that temperature energy added to the blackbody is increasing the rate that an atom of the blackbody emits a photon at, i.e. an increase in rate of electron transitions, and consequently the quantum energy level of the atom that then emits a higher energy, higher rate/frequency of photon.Planck calculated the energy increases via an invariant second. Calculate the temperature energy added via the rate (second) of the emitted frequency and the quantum nature is negated.

where a is either increasing or decreasing due to a potential energy to kinetic energy conversion

(where relativistic mass in relation to kinetic energy for light in current physics remit ensures 0 acceleration/deceleration)

I am not sure what the simplifications you wish to make are...Is it setting speed at 0 on the outbound?

in which case traveller speed at the altitude in question is sqrt(2GM/r).