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f(x)=xf(-x)≠xf(yz)=x±(0/1)(x,y,z)=f(x)+f(yz)∅=∞0=1

sorry i forgot to add "0≠0" after that.

Quote from: Ve9aPrim3 on 17/02/2018 20:16:32sorry i forgot to add "0≠0" after that.You forgot to add something that's plainly not true...

There is actual, real mathematics that can be done when 0=1. Maths done modulo 1 is like that.Then 0.1 + 0.1 = 0.2 but 0.5 + 0.5 = 1 = 0

Analogue clocks work on continuous modulo mathematics after all.

Of course it does. It leads to no conceptual difficulties. Analogue clocks work on continuous modulo mathematics after all.On the other hand: 0 ≠ 0is far more tricky, I doubt that works with any equality operator that does anything very conventional or useful.

They're only marked at integer spacings, but the hands are moving continuously and have a fractional position at all times.