Yes, to amplify that a bit... If you are asking how much energy is lost during a 90 degree turn of an object initially in rectilinear motion, the answer is zero, unless there is some other lossy interaction. Newtons second law, F=mA, is a vector relationship, and in performing this 90 degree turn, the force applied to the moving mass, m, is at 90 degrees to the path of the mass at all times. The energy expended is described by a vector "dot product", which is always zero when the angle between the two factors is 90 degrees. The speed of the mass is the same after the turn, although the velocity of the mass has turned by 90 degrees.

Look for a college physics textbook in your local library, and go find "uniform circular motion" for a complete explanation.