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I have been using my relativity program i made in 1997 and have some ideas. Do massless particles travel along with the actual speed of the expansion of the universe close to C

, , , , Is the apparent rate of the expanding universe 44.7387 mile per second per mega parsec, and does it work out at an actual rate of 99.999999 C

here is a screen shot of my program

Note the actual speed of .99999997, or 186243 MPS

and the apparent speed at the bottom of 64.30355 MPS

TIME DILATION IS 2896.309

Hi Halc , , , I have checked my time dilation program results and they are correct

.999 works out at 22.36649 times dilation and .8 is 1.666667, my program works fine

i believe i am correct in my observations that there is an actual and apparent effect, and that the expansion rate of the universe has an apparent value.

Hi Halc, , Like I said, my program is accurate and works out the same on paper, I suggest you try it with .999 and .8

if you were a stationary observer on earth, and i got in a space ship on a round trip to the moon and back at a speed of 87% the speed of light there would be a 2x time dilation, it would take me 3 seconds, but when i returned to earth you would say ive been gone 6 seconds.

FROM EARTHS VIEW APPARENTLY THE TRIP TOOK 6 SECONDS WHEN IN FACT FROM THE SHIPS VIEW IT ACTUALY TOOK 3 SECONDS, DIFFERENT TIMES

I can understand that it all seems counter intuitive, but its just a basic Special Relativity concept

I shall post you my QBASIC program TXT

Hey halc, Hmmmm i did it on paper, you may be right.99999997.99999994.00000006.0002449481 / 000244948 = 4082.499 not my 2896.309Arghhhhhhhhhhh, , , i will have to debug it , , ,Eeeeek !! it could be my calculator tho, im gona try .99999

Yes, spot on the apparent speed is .435 and the actual speed is .87, 2 x dilation

Your getting the idea but this is wrong "The final time will still be 3 seconds (me) and 1.5 seconds (ship)".it should be 6 and 3I can understand that it all seems counter intuitive, but its just a basic Special Relativity concept

Yes halc this is correct, if the faster ship is going fast enough, it would loose every time , ,it obviously depends on how fast and far the slow ship is moving, and how long the round trip took for it, ,

90 INPUT "ENTER T1 "; T1: INPUT "ENTER V"; SP: PER = SP