Naked Science Forum

On the Lighter Side => New Theories => Topic started by: Ve9aPrim3 on 17/02/2018 06:15:47

Title: Eureka!!! f(yz)!!! --- (x,y,z)=f(x)+f(yz) --- A 100% Variable equation
Post by: Ve9aPrim3 on 17/02/2018 06:15:47
Finally! I think I may have found the condensed version that every one can understand. What I have been begging for everyone to understand.

f(x)=x
f(-x)≠x
f(yz)=(f(x)≠x)±(0/1)

(x,y,z)=f(x)+f(yz)
Title: Re: Eureka!!! f(yz)!!! --- (x,y,z)=f(x)+f(yz) ---
Post by: Colin2B on 17/02/2018 08:45:48
Try explaining it in words and we will check your understanding.
Title: Re: Eureka!!! f(yz)!!! --- (x,y,z)=f(x)+f(yz) ---
Post by: evan_au on 17/02/2018 10:07:26
Quote
the condensed version that every one can understand
Put me down as a failure.
Title: Re: Eureka!!! f(yz)!!! --- (x,y,z)=f(x)+f(yz) ---
Post by: guest39538 on 17/02/2018 13:32:32
Quote from: Ve9aPrim3 on 17/02/2018 06:15:47
Finally! I think I may have found the condensed version that every one can understand. What I have been begging for everyone to understand.

f(x)=x
f(-x)≠x
f(yz)=(f(x)≠x)±(<1/≥1)

(x,y,z)=f(x)+f(yz)

Dude ,

ƒ: Rn = 0

ƒ: Rn = ƒ: Rn

ƒ:x=y=z=t=λ=0

Title: Re: Eureka!!! f(yz)!!! --- (x,y,z)=f(x)+f(yz) ---
Post by: Ve9aPrim3 on 17/02/2018 14:31:31
Quote from: Thebox on 17/02/2018 13:32:32
Dude ,

ƒ: Rn = 0

ƒ: Rn = ƒ: Rn

ƒ:x=y=z=t=λ=0
Dude,
That may as well be mandarin to me.
Let me further clarify... or at least try.
f(yz)=(f(x))/2 (as long as i'm here, "/2" is supposed to mean rotated by 180 degrees)
Now find the intercept point! Singular!
(x,y,z)

You end up with Infinite Non-answers and just 1 answer.
-or-
∅=∞
-or-
"±" = "=≠"

Balancing equations with "±" just means it's "= AND ≠"
 
Title: Re: Eureka!!! f(yz)!!! --- (x,y,z)=f(x)+f(yz) ---
Post by: guest39538 on 17/02/2018 14:35:17
Quote from: Ve9aPrim3 on 17/02/2018 14:31:31
Quote from: Thebox on 17/02/2018 13:32:32
Dude ,

ƒ: Rn = 0

ƒ: Rn = ƒ: Rn

ƒ:x=y=z=t=λ=0
Dude,
That may as well be mandarin to me.
Let me further clarify... or at least try.
f(yz)=(f(x))/2 (as long as i'm here, "/2" is supposed to mean rotated by 180 degrees)
Now find the intercept point! Singular!
(x,y,z)

You end up with Infinite Non-answers and just 1 answer.
 
Your math looks ''Mandarin'' to me.   

R represents real number dimensional space,  n is any dimension, the function of any Universe would be ƒ: Rn = 0  because 0 = infinite.
Title: Re: Eureka!!! f(yz)!!! --- (x,y,z)=f(x)+f(yz) ---
Post by: Ve9aPrim3 on 17/02/2018 18:41:10
Quote from: Thebox on 17/02/2018 14:35:17
R represents real number dimensional space,  n is any dimension, the function of any Universe would be ƒ: Rn = 0  because 0 = infinite.
But

IF
(x,y,z)=(f(x)=x)+(f(x)≠x)±(<1/≥1)
TRUE
THEN
0=1
ELSE
0=0


Which I suppose could be writen as
(x,y,z)=(f(x)=x)+(f(x)≠x)±(0/1)
Title: Re: Eureka!!! f(yz)!!! --- (x,y,z)=f(x)+f(yz) --- A 100% Variable equation
Post by: Bored chemist on 17/02/2018 19:57:56
An argument between thebox and Ve9aPrim3

I may have to buy popcorn.
Title: Re: Eureka!!! f(yz)!!! --- (x,y,z)=f(x)+f(yz) --- A 100% Variable equation
Post by: Colin2B on 18/02/2018 09:28:09
OP has requested all further discussion be directed to https://www.thenakedscientists.com/forum/index.php?topic=72397.0

So this topic is now locked