[Ve9aPrim3 (OP)]

Finally! I think I may have found the condensed version that every one can understand. What I have been begging for everyone to understand.

f(x)=x
f(-x)≠x
f(yz)=(f(x)≠x)±(0/1)

(x,y,z)=f(x)+f(yz)

[Colin2B]

Try explaining it in words and we will check your understanding.

[evan_au]

the condensed version that every one can understand

Put me down as a failure.

[guest39538]

Finally! I think I may have found the condensed version that every one can understand. What I have been begging for everyone to understand.

f(x)=x
f(-x)≠x
f(yz)=(f(x)≠x)±(<1/≥1)

(x,y,z)=f(x)+f(yz)

Dude ,

ƒ: R_n = 0

ƒ: R_n = ƒ: R_n

ƒ:x=y=z=t=λ=0

[Ve9aPrim3 (OP)]

Dude ,

ƒ: Rn = 0

ƒ: Rn = ƒ: Rn

ƒ:x=y=z=t=λ=0

Dude,
That may as well be mandarin to me.
Let me further clarify... or at least try.
f(yz)=(f(x))/2 (as long as i'm here, "/2" is supposed to mean rotated by 180 degrees)
Now find the intercept point! Singular!
(x,y,z)

You end up with Infinite Non-answers and just 1 answer.
-or-
∅=∞
-or-
"±" = "=≠"

Balancing equations with "±" just means it's "= AND ≠"
 

[guest39538]

Dude ,

ƒ: Rn = 0

ƒ: Rn = ƒ: Rn

ƒ:x=y=z=t=λ=0

Dude,
That may as well be mandarin to me.
Let me further clarify... or at least try.
f(yz)=(f(x))/2 (as long as i'm here, "/2" is supposed to mean rotated by 180 degrees)
Now find the intercept point! Singular!
(x,y,z)

You end up with Infinite Non-answers and just 1 answer.
 

Your math looks ''Mandarin'' to me.   

R represents real number dimensional space,  n is any dimension, the function of any Universe would be ƒ: Rn = 0  because 0 = infinite.

[Ve9aPrim3 (OP)]

R represents real number dimensional space,  n is any dimension, the function of any Universe would be ƒ: Rn = 0  because 0 = infinite.

But

IF
(x,y,z)=(f(x)=x)+(f(x)≠x)±(<1/≥1)
TRUE
THEN
0=1
ELSE
0=0


Which I suppose could be writen as
(x,y,z)=(f(x)=x)+(f(x)≠x)±(0/1)

[Bored chemist]

An argument between thebox and Ve9aPrim3

I may have to buy popcorn.

[Colin2B]

OP has requested all further discussion be directed to https://www.thenakedscientists.com/forum/index.php?topic=72397.0

So this topic is now locked