Naked Science Forum
On the Lighter Side => New Theories => Topic started by: Ve9aPrim3 on 17/02/2018 19:25:28
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Proof:
f(x)=x
f(-x)=f(yz)
f(yz)=x±(0/1)
f(xyz)±f(x)+f(yz)
∅±∞
0±1
f(yz)
=
(0/1) ± x ± (0/1)
=
f(yz)
...........
f(x)=x
f(-x)=f(yz)
f(yz)=x±(0/1)
f(xyz)=f(x)+f(yz)
∅=∞
0=1
I just pictured equations being balanced differently I guess.
1=1
1≠-1
1±1
All these mean the same to me.
"=" is how you balance an equation horizontally.
"±" is how you balance an equation across 3D space.
...Whoops..I mean
f(x)=x
f(-x)=f(yz)
f(yz)=x±(0/1)
f(xyz)±f(x)+f(yz)
∅±∞
0±1
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Gibberish.
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Gibberish.
f(x) is used to calculate intercept points across 2D space.
0=1 is used to calculate the intercept point across 3D space.
Working with "f(x)" is a great tool in 2D computation, but "0=1" is much more practical in 3D computation.
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f(yz)=x±(0/1)
f(yz)
=
(0/1) ± x ± (0/1)
=
f(yz)
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Gibberish.
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Why do you bother? You must have something more productive you could be doing. Like popping bubble wrap.
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