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Quote from: Jaaanosik on 01/02/2024 11:29:52If y≠y' then does it mean the Lorentz transformation is 'broken'?Why would it be?
If y≠y' then does it mean the Lorentz transformation is 'broken'?
We see y≠y'
Quote from: Jaaanosik on 02/02/2024 12:31:21We see y≠y' I must be missing something because it looks like y=1 and y'=1 on your illustrations.
Changing the perspective as shown in Figure 9 and Figure 10, suddenly y!=y'.Is that correct? Do you agree?
Figure 7: The train light round-trip observed from the platform inertial reference frame.
Figure 10: The second red photon in the train grid of inertial observers at time t'=2s'.
We see y≠y' for the platform light round-trip between t>2s and t<=4s.
The proper time between two inertial grids cannot be synchronized.
The Lorentz transformation inherently determines who is looking at a specific event.
Here is a space-time diagram to ponder.Figure 11: Train car space-time diagram for the train time t'=2s'.
Just to demonstrate the problem. The event of reception at the platform observer does not exist for the train grid of inertial observers yet. It is in the future.
SR does not posit a past/present/future ontology for events. Doing so would contradict the first premise of SR. So any mention of these is meaningless.The event of reception at the platform observer(s) do very much exist in your picture. You label at least one of them and everything.