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The sum of energy in a rotation
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The sum of energy in a rotation
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LB7
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Ludovic Bavay Ubeda
The sum of energy in a rotation
«
on:
03/06/2016 23:26:45 »
The study:
A force turns around the center O in a circle (dotted lines), the force keeps its angle with the radius (beta is constant = 30°). The radius of the circle is 1. The force is 1. An external device gives the force F. It's easy to calculate the work needed to rotate the force from 0° (vertical) to 90° it is 0.5 from vertical to horizontal (rotate of 90°).
Now, take the black arm. The black arm turns around the red point, but it takes the force F at the end and it must increase its length if I want the force F turns around the center O.
Now the work is :
There is a difference !
Maybe I need to do that:
But there is always a difference:
2*cos(x)*sin(x+pi/6)-2*sin(x)*cos(x+pi/6) dx from pi/4 to 0
I found my error, it was the length in the integration. The sum of energy is 0.
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Last Edit: 04/06/2016 13:24:01 by LB7
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Ludovic Bavay 19011971 Valenciennes
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