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Physics, Astronomy & Cosmology / The rotational energy of a maximal rotating black hole
« on: 08/01/2009 10:41:45 »
also you could use the energy of rotation formula K=1/2(l)(omega)^2 and using I=(2/5)*mr^2 and use the mass and finding the radius would prove to be a trick but if you know what you're doing you'll know that the units omega or the rate of rotation in radians is the inverse of the radius squared and all you are left with is 1/2mv^2 or just plugging in numbers will give you the same answer with the 1/2