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SR mentality claims that the photon always moves away from its source by the speed c.
8.66 rocketsecond
We may think that: The 33.3 % of the distance is traveled by the Earth/observer. While the photon comes toward to the Earth, the Earth also approaches to the photon. The photon that 6.6666 c of the way with its constant velocity c. Please think the process on four dimensions. The Earth is not motionless. While the actors travels the intermediate distance decreasing and the meeting is realized at 6.6666 second. It does not mean that the photon scans the way of 10 c for the time 6.666 second. All of the event and math is logic.But SR claims that the photon uses 8.66 rocketsecond for the 10 c way (please look at my former message for math.
I really do not understand your ideas. I thought you said that the speed of light and the speed of the source was a straight addition, now it seems like it isn't, so I am confused. I think it would be best for me to tell you how I see this scenario occurs and then you can tell me how you see it.So the scenario is a rocket is moving relative to earth at .5 c in the direction of earth and it shoots a laser towards earth when it is 10 Ls from earth. From the earths frame the rocket would be moving at .5c towards earth and the laser would be shot at 10 Ls from earth. The light would take 10 seconds to reach earth and the speed of light would be measured as c by both the earth and the rocket. The rocket would take 20 seconds to reach earth. From the rockets frame the earth would be moving at .5 c towards the rocket and the rocket would shoot the laser when the earth was at a distance of 10 Ls from the rocket. The light would take 6.6666 sec to reach the earth because the earth would have moved 3.333 Ls closer to the rocket. The speed of light as measured by both the rocket and the earth would be c. The earth would reach the rocket after 20 seconds.Would your idea have a different answer than this?
The reason of confusing may be to choise as the reference frame either the Earth or the rocket in the same analysis. We are allowed for one of them (for relativity method).
1- According to SR mentality: the photon which emitted from rocket travels the distance(L = 10 proper/inert second x c) for 8.66 rocketsecond.
2- According to LCS mentality:2.1- Classical / Galilean relativity rules is valid ( like in elementary or medium school).
2.2- We have to use a common reference frame. This frame must be most external frame in universe for light actor. So, it is space or LCS.The all speeds (light's, Earth's, rocket's) must be adapted according to this outer space.
2.3 The emitting/leaving point of the photon is marked on LCS (rocket has passed on this point at emitting moment).2.4 By these conditions, my figures 1 clearly explaines the light kinematics event for your example. Contact time : t = L / (Vu (earth) + c) = 6.666 LCS second.
3- On my figure 2: Another option of 1.5 c velocity event is exhibited. If the Earth goes to opposite direction (toward -x ) of the photon (the earth's speed 0.5 c) ; intermediate distance between the photon and its source will increase with 1.5 c although the photon has the speed c. This relative speed can be called as "hypothetical/pseudo relative speed".
That is not correct. From the earth frame the photon takes 10 seconds to reach earth and from the rockets frame the photon takes 6.666 seconds to reach earth. Neither frame thinks it takes 8.66 seconds.
...rocketsecond ...inertsecond...
Never mind moving on from 2.4xersanozgen Every single test of relativity has shown that it gets the right answer.Does your idea give the same answer as relativity?If it does then it is redundant.If it does not then it is wrong.There is no option where your idea is useful.
Are you sure that you know the theory of special relativity?Before, you have to confirm 8.66 rocketsecond for rocket's speed 0.5 c according to 10 inertsecond; then we may continue to discuss more advanced options.
So the scenario is a rocket is moving relative to earth at .5 c in the direction of earth and it shoots a laser towards earth when it is 10 Ls from earth.
From the earths frame the rocket would be moving at .5c towards earth and the laser would be shot at 10 Ls from earth. The light would take 10 seconds to reach earth and the speed of light would be measured as c by both the earth and the rocket. The rocket would take 20 seconds to reach earth.
From the rockets frame the earth would be moving at .5 c towards the rocket and the rocket would shoot the laser when the earth was at a distance of 10 Ls from the rocket.
The light would take 6.6666 sec to reach the earth because the earth would have moved 3.333 Ls closer to the rocket. The speed of light as measured by both the rocket and the earth would be c. The earth would reach the rocket after 20 seconds.
Would your idea have a different answer than this?
SR has a different answer. The distance between Earth and the light emission event is length contracted to 8.66 Ls in the rocket frame:
After I share the link of my new paper (An experiment for special relativity), I will end my messages on this topic.
Every single test of relativity has shown that it gets the right answer.Does your idea give the same answer as relativity?If it does then it is redundant.If it does not then it is wrong.There is no option where your idea is useful.
I want to share a new study about special relativity: One way speed of lightAbstract: The velocity of light is measured by a light-specific method (mirrored double paths, uninterrupted photons, etc.). In this study an experiment is presented with a single photon and one way path. Thus, the increasing speed of the distance between the photon and its source can be measured and the essence of special relativity theory can be questioned. If this experiment can be realized, Earth’s momentary universal speed can be detected. The measurement direction which gives maximum and minimum values will be interpreted about current expanding speed of universe and expanding direction.Link: https://vixra.org/abs/2006.0224
QuoteIt's not a measure of the one way speed of light.The speed of light has been measured on single path with atomic clock and the value c never be provided.https://en.wikipedia.org/wiki/One-way_speed_of_light
It's not a measure of the one way speed of light.
Quote from: Bored chemist on 26/06/2020 11:27:48 QuoteIt's not a measure of the one way speed of light.The speed of light has been measured on single path with atomic clock and the value c never be provided.https://en.wikipedia.org/wiki/One-way_speed_of_lightDid you read the wiki page you cited?It says "The "one-way" speed of light, from a source to a detector, cannot be measured "And it's right.
It says "The "one-way" speed of light, from a source to a detector, cannot be measured "And it's right.
Using the system, Marmet [18] observed that GPS measurements show that a light signal takes about 28 nanoseconds longer traveling eastward from San Francisco to New York as compared with the signal traveling westward from New York to San Francisco. Kelly [19] also noted that measurements using the GPS reveal that a light signal takes 414.8 nanoseconds longer to circumnavigate the Earth eastward at the equator than a light signal travelling westward around the same path. Marmet and Kelly both concluded that these observed travel time differences in the synchronized clock measurements in each direction occur because light travels at speed c−veastward and c+vwestward relative to the surface of the earth. Herevis the speed of rotation of the Earth’s surface at the particular latitude. This research by Marmet and Kelley was the precursor to a series of papers by this author on the use of GPS technology in the unambiguous demonstration of one-way light speed anisotropy.