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As a consequence, the photon that is captured and stored by an electron, is the same photon that is subsequently released by that electron
If a particle gets hit by a massless photon traveling at the speed of light then it has to be the energy of the photon that counts.
So I'm considering that the photon that space "tried" to create when leaving A, is not the same photon after a mili second after towards B...
We are moving on with errors on our math since day one, this on everything, necessarily assumptions to eventually reach reality...
You need to distinguish between several different photoelectric phenomena1. prompt release of a conduction electron2. ionisation and single electron release3. Auger ionisation4. Compton scatter5. metastable trapping (as in lasers)6. stable trapping (F-center traps)7. molecular restructuring8. fluorescenceEach of these has a different mechanism and a different lifetime in the excited state. 1,5, 6 and 7 are not associated with photon emission. Compton scatter is effectively prompt. Single-electron ionisation will be followed by reorganisation of the remaining electrons to achieve the lowest energy configuration of the atom and as a first approximation you can assume that each transition takes 1/f seconds where f is the frequency of the associated photon that will be emitted by that transition. There is no "trigger" requirement. Indeed stable and metastable trapping are the only photoelectric phenomena that lead to a triggerable subsequent photon release, and in each case the triggering event is the arrival of another photon of sufficient energy to raise the trapped electron over the trap barrier. Above 1.022 MeV a photon can interact with the field of a nucleus to produce an electron-positron pair whose subsequent annihilation generates two more photons. The lifetime of "positronium" is about 125 picoseconds.