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Quote from: Kryptid on 07/04/2022 21:50:42Quote from: Yahya A.Sharif on 07/04/2022 21:45:35It shouldn't make that big difference of jumping fast against gravity and barely moving the rockOkay, prove it (and do it with an actual, good argument, not mere intuition).A person stands on a scale he holds a15 kg block on his hands and his arms are stretched out in front of his body in which his arms make a lever its fulcrum is at the elbow. The position is equivalent to trying to pick a fruit on a tree in which the fulcrum is at the toes . If he lifts the rock up as a lever the scale will read 15+60 kg that is the 15 kgf is the force he lifts the rock with which equals to the mass of the rock 15 kg. As the rock 15 kg needed 15 kgf, a rock of 60 kg will need a 60 kgf.Lifting the rock will need a 60 kgf lifting or jumping with his body will need a very smaller force x kgf. That why he can jump fast against gravity but he will barely move a rock of 60 kg.
Quote from: Yahya A.Sharif on 07/04/2022 21:45:35It shouldn't make that big difference of jumping fast against gravity and barely moving the rockOkay, prove it (and do it with an actual, good argument, not mere intuition).
It shouldn't make that big difference of jumping fast against gravity and barely moving the rock
Quote from: Yahya A.Sharif on 07/04/2022 20:13:30my experiments say: as I can jump around easily I can lift my body with small force x*9.8 N too.Sorry to jump in.However, what is so unique in your jump?I can offer you several animals with a similar mass that can jump and lift much better than you do.So why do you focus on the human body mass?Why don't you focus on the human brain ability/mass?Just think about it - You won't find any creature/animal in the entire planet that would claim that its body mass is special.
my experiments say: as I can jump around easily I can lift my body with small force x*9.8 N too.
jumping with his body will need a very smaller force x kgf.
A person stands on a scale he holds a15 kg block on his hands and his arms are stretched out in front of his body in which his arms make a lever its fulcrum is at the elbow. The position is equivalent to trying to pick a fruit on a tree in which the fulcrum is at the toes . If he lifts the rock up as a lever the scale will read 15+60 kg
Quote from: Yahya A.Sharif on 10/04/2022 13:29:13A person stands on a scale he holds a15 kg block on his hands and his arms are stretched out in front of his body in which his arms make a lever its fulcrum is at the elbow. The position is equivalent to trying to pick a fruit on a tree in which the fulcrum is at the toes . If he lifts the rock up as a lever the scale will read 15+60 kgNo, you don't have to lift the 15 kg weight. If you hold perfectly still holding the 15 kg weight your combined weight will measure 15 + 60 kg.
If you raise the 15 kg weight the scale will read 15 + 60 + x kg. The 'x' will be a small percentage of the weight while you are lifting it but when you stop lifting it the scale will return to the 15 + 60 kg
It will read 75+15+x this is if he raises the total, his body and the rock with his feet. 75 kg what the scale first reads adding to it x kgf to lift the body and 15 kgf to lift the rock a total of 75+15+x kg
But if he raises the rock up by his arms he lifts the 15 kg alone because his body didn't move upwards.The scale will show 75+15 the force the scale shows 75 kgf plus the force he lifts the rock with 15 kgf.
Quote from: Yahya A.Sharif on 10/04/2022 15:35:04It will read 75+15+x this is if he raises the total, his body and the rock with his feet. 75 kg what the scale first reads adding to it x kgf to lift the body and 15 kgf to lift the rock a total of 75+15+x kgNo that is not correct. It would be 75 + x kg.
No that is not correct. When you are on the scale holding the rock the force on the scale is 75 kg (60 + 15). You can look at it like this; when the rock is held steady, your body and the rock are accelerating at 9.8 m/s^2. So when the rock is not moving:F = (60 x 9.8 m/s^2) + (15 x 9.8 m/s^2) = 735 NLet's say you raise the rock 1 meter in a second. That is roughly an acceleration of 2 m/s^2. So the overall acceleration of the rock is:9.8 m/s^2 + 2 m/s^2 = 11.8 m/s^2So when the rock is moving:F = (60 x 9.8 m/s^2) + (15 x 11.8 m/s^2) = 765 NSo when the rock is moving the scale will read about (765 N) / (9.8 m/s^2) = 78 kg, which is 60 + 18 kg.
will not be able to add the 15 kg to the 60 kg because one of them is human and the other is object .
You seem to be missing the point.In science, just saying "This will happen" is not good enough.You have to actually show that it does happen.And, from what we already know, it will not actually happen.Just typing words on teh internet does not change reality.
The person instead of consisting of human body 75 kg he is 60 kg human and carries an object 15 kg I will not be able to add the 15 kg to the 60 kg because one of them is human and the other is object
The person instead of consisting of human body 75 kg he is 60 kg human and carries an object 15 kg I will not be able to add the 15 kg to the 60 kg because one of them is human and the other is object .
If you drink 1 kg of water, your weight becomes 61 kg. How can the scale distinguish between your original weight and the weight of the water?
Quote from: hamdani yusuf on 11/04/2022 04:33:17If you drink 1 kg of water, your weight becomes 61 kg. How can the scale distinguish between your original weight and the weight of the water?Are you serious?!Here is the answer, it is a tough one but I will try and answer it - before you drink the water you weigh 60kg and after you drink the water you will weigh 61kg and scales measure weight!
Nobody understand.
Quote from: Origin on 11/04/2022 16:27:03Quote from: hamdani yusuf on 11/04/2022 04:33:17If you drink 1 kg of water, your weight becomes 61 kg. How can the scale distinguish between your original weight and the weight of the water?Are you serious?!Here is the answer, it is a tough one but I will try and answer it - before you drink the water you weigh 60kg and after you drink the water you will weigh 61kg and scales measure weight!It looks like you are missing the context.
Quote from: Yahya A.Sharif on 10/04/2022 17:57:00The person instead of consisting of human body 75 kg he is 60 kg human and carries an object 15 kg I will not be able to add the 15 kg to the 60 kg because one of them is human and the other is object .If you drink 1 kg of water, your weight becomes 61 kg. How can the scale distinguish between your original weight and the weight of the water?
A human weight is 60 kg doesn't change. Water weight is 1 kg doesn't change. The scale shows 61 kg, water weight plus human weight.
It is simple. No magical scales are needed. It is just a matter of calculations:A human weight is 60 kg doesn't change. Water weight is 1 kg doesn't change. The scale shows 61 kg, water weight plus human weight. He lifts his body alone before drinking water with x kgf and 1 kg mass needs 1 kgf to be lifted . So the force to lift both after drinking is x+1 kgf The scale will change from first measurement 61 kg to 61+(x+1) kg, the force he lifts his body with x+1 kgf plus the first read 61 kgf.
Quote from: hamdani yusuf on 13/04/2022 04:51:04A human weight is 60 kg doesn't change. Water weight is 1 kg doesn't change. The scale shows 61 kg, water weight plus human weight.You figured it out. Good.
The scale will change from first measurement 61 kg to 61+(x+1) kg, the force he lifts his body with x+1 kgf plus the first read 61 kgf.