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New Theories / Re: Re: Law of Conservation of Energy?
« on: 16/10/2021 08:36:27 »
Some of the lights energy in this idea is given up to collisions as well which I should have said, but it's still all accounted for.
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Newtons are a measure of force, by definition. If you are measuring newtons, you are measuring force.
No because general relativity is from first principles, a classical pseudo force. What do we mean by this?
It's equivelent to saying gravity is a "false" force.
Centrifugal force is a "false" force too, but it's still a force nonetheless. Otherwise, you couldn't measure it in newtons.
You're failing, intentionally, to listening to what I am saying.
I know what you're saying, but that doesn't mean that gravity doesn't produce a force.
That equation doesn't make sense. You can't put a physical objects like electrons and protons into an equation.
Of course not but you can create a physics formula that describes the physics without any falsities and very simple to understand instead of energy equivalents that come across as nonsense to most people .
Everyone can understand that an atoms components are composed of Protons and Electrons and atoms have a volume .
Atoms are energy are they not ?
Of course you can also expand on this and do numbers if you like but this is easy to understand and also applies to quantum fields emitted by the convergence of a proton and electron .
I hope that Bogey person reads this thread !
F = mg is completely redescribed by curvature in GR. Not force.
You know that that "F" in that equation is force, right?
It's not a force.
Then my bathroom scale wouldn't measure anything.
What you experience is space pushing down on you.
And that push is a force.
Not quite. A real field that exerts a force requires a mediator. Gravity is manifestly a pseudo force.
If you don't think gravity exerts a force, then I'm guessing you've never used a bathroom scale before.
A photons path is bent by bent space so certainly there must be a force on the photon? (change of momentum occurs).
Yes, in that case, gravity does indeed exert a force on the photon in question.
A photons path is bent by bent space so certainly there must be a force on the photon? (change of momentum occurs).
A photons path is not ''bent'' by ''bent'' space ! Firstly the word we use is curvature , not ''bent'' .
A photon travels in general a straight path unless it is deflected or reflected etc . Additionally photons tend to travel where ever the energy is required but this is also what we call linear vectors .
A single photon has a very limited force because of the formula E=mc^2 but a ''packet'' of photons can exert more force as observed in the photon electrical effect .
When considering the mass and force involved in photons it is better to consider them in a XY format rather than a singular photon !
Visual matter can absorb a single photon potential energy no bother but when bombarding with lots of photons , Newtons third law applies and the visual matter ''pushes back'' in the form of photon electrical effect .
@BilboGrabbins
Hi there!
🙋
I have a Query, Especially for You.
Interested?
A_______B
A simple line.
Start point A.
End point B.
I suppose i can keep dividing it into Halves.
But considering Planck's Length, Can i Divide it until Infinity?
If i Know the Line's point of Origin(A) & am Aware of the Line's point of Cessation(B)...Does that sound like Infinity?
Or if i didn't know the Origin, n was clueless bout the End.
Infinity!
Ps - Thanks E_S for the suggestions.
I've Realized my capacity to understand & learn is Not infinite.
Hence i do not bother myself, & also spare Others of goin thru the troubles of explaining me things which i Firmly Believe i shall never understand.
(Reason i Request for short & brief answers, i Hate it when Teachers waste their Precious Time on Futile Things)
: )