0 Members and 1 Guest are viewing this topic.
if anyone knows how capacitor will lose it's energy, please reply.
Work is done when charging or discharging a capacitor ...
Are you saying you know it won't work but you'd like to understand why, or are you saying it does work?If you believe it works, I'm afraid we'll have to move it to "New Theories".
Hello everyone.There's an idea that bugs me for last few years. I've tried consulting few PhDs and got no answers, and I have no materials to do this experiment on my own.I know that this device shouldn't work, but I have no idea why. Let's say that we have a charged capacitor. Let's use most simple version of capacitor - two parallel conductive plates that have same dimensions and we charge those plates to say... 100V (doesn't matter, really).Place closed coil of wire around one plate. The coil should enter capacitor space near -100V charged plate, and exit capacitor space near +100V charged plate, so there should be nice difference in potential energy of free electrons in coil that are near +100V plate and those that are close to -100V plate.In theory, capacitor energy is defined only by its voltage levels and capacitance. Since capacitor is charged, and disconnected, the voltage levels should stay the same, and since it is rigidly built, it should not change it's capacity.Electric field should appear as soon as we charge the capacitor, and it should exist only between capacitor plates. This field should start moving free electrons in coil thus producing a current in coil circuit. Now, if we place resistor in coil circuit the current generated in coil should generate heat in resistor transforming electrical energy in heat.The question is obvious. Only energy that we provided to this system was energy used to charge capacitor, and now we have heat constantly generated by current passing through resistor, and capacitor should maintain its voltage levels...So, if anyone knows how capacitor will lose it's energy, please reply. Don't bother with imperfection of regular capacitor, I know it will "run dry" by itself. I want to know how it loses its energy when it transfers it to electrons in the coil.Thank you! PS Please excuse any grammatical and spelling mistakes that I made.
Coil + capacitor isn't that an LC oscillator circuit ? ... http://en.wikipedia.org/wiki/LC_circuit#Operation (the oscillations die away, they don't continue perpetually )
So the coil makes contact with neither capacitor plate?