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Physics, Astronomy & Cosmology / If I give an object some potential energy, does its mass increase?
« on: 03/02/2010 06:03:25 »SpaceTime is no static geometry, not according to me at least? As for that times arrow is about 'change' or as some say 'events' there is no doubt. But the question I asked was how you thought about 'changes' taking shorter or longer 'time' to happen depending on your frame of observation.I said that my ideas on this topic were not fully fleshed out. But certainly time is the thing that allows one geometrical arrangement to become a different geometrical arrangement. One particle can at most have one interaction during one time quantum. This is not the same thing as saying that one time quantum only allows one interaction in the Universe to take place. The time quantum affects the entire universe at once; different interactions happen in different locations during that quantum of time. The type of interaction that each particle engages in, during that quantum of time, depends on the particle's neighbors, not on the time quantum.
If you think of time 'changes' and watch that clock (observing it) hang at the event horizon, there are going to be an awful lot of changes happening to you before that clock ever moves a inch you will have died long before that. And that was the crux of it to me. How you saw those 'time quanta' as differing between different observations from different 'frames of reference'. The clock tick as usual from its own perspective, but you, the earth and the universe is accelerated and blueshifted, changing at a ever increasing pace as it falls in.I don't see any time quantum as being different from any other time quantum. Each one is the same, Universe-wide. The interactions that occur, at different places in the universe, depend only on what neighbors each particle is interacting with.
A clock that has no other neighbors will have all its parts interacting only with each other during each time quantum. A clock with lots of neighbors will have at least some of its parts interacting with those neigbhors, during each time quantum. The net effect is that the isolated clock runs faster, because it takes more time-quanta for the crowded clock to do the same purely internal interactions as the isolated clock.
So how do you equate those two observations with your 'time quanta'? Consider A here as the the minute hand ticking one minute as seen from the frame of the in-falling clock. Here is 'time quanta A' as seen from the frame of the clock, with its time 'as usual' so to speakNo infinity; the available evidence strongly suggests the Universe is finite. (Example, an infinite universe would be associated with infinite gravitation, and we'd all be in a black hole as a result.) The reference frames you describe are ignoring the available neighbors, for interacting. Remember that even a vacuum is full of virtual particles with which interactions can occur, and a speeding reference frame can encounter more of those virtual particles than a stationary reference frame, in any specified number of time quanta (the speeding frame has more neighbors).
<-A->
Here it is from the perspective of you observing the clock.
<-------------------A------------------->
That 'time quanta', lifted from the perspective of the clock, will now contain a infinite amount of 'changes/events' from your perspective observing. You can travel home to Earth and come back without that clock hand ever moved according to you.