The Naked Scientists
  • Login
  • Register
  • Podcasts
      • The Naked Scientists
      • eLife
      • Naked Genetics
      • Naked Astronomy
      • In short
      • Naked Neuroscience
      • Ask! The Naked Scientists
      • Question of the Week
      • Archive
      • Video
      • SUBSCRIBE to our Podcasts
  • Articles
      • Science News
      • Features
      • Interviews
      • Answers to Science Questions
  • Get Naked
      • Donate
      • Do an Experiment
      • Science Forum
      • Ask a Question
  • About
      • Meet the team
      • Our Sponsors
      • Site Map
      • Contact us

User menu

  • Login
  • Register
  • Home
  • Help
  • Search
  • Tags
  • Recent Topics
  • Login
  • Register
  1. Naked Science Forum
  2. Non Life Sciences
  3. Physics, Astronomy & Cosmology
  4. Force of impact question
« previous next »
  • Print
Pages: [1]   Go Down

Force of impact question

  • 6 Replies
  • 4679 Views
  • 0 Tags

0 Members and 1 Guest are viewing this topic.

Offline willpower (OP)

  • First timers
  • *
  • 1
  • Activity:
    0%
Force of impact question
« on: 27/04/2012 15:51:42 »
I drop a 1kg weight from a meter in height and it decelerates to a stop in 0.1 of a meter (total distance travelled 1.1 meters)
What force is applied to the impact object?
What force is applied to the falling object? (assuming no deformation)
All assuming no air resistance and no bouncing
Logged
 



Offline Æthelwulf

  • Sr. Member
  • ****
  • 358
  • Activity:
    0%
Re: Force of impact question
« Reply #1 on: 27/04/2012 18:33:28 »
Well, what equations have you learned for the question? I assume this is homework. I'll steer you in the right direction:

cc65543213195fc865abb882d2d8b793.gif

The force is fec132e4cdab9fbb63ac9378495cc684.gif and weight is also a force e45d00b99ba27b8fe31372beac1fe720.gif.
« Last Edit: 28/04/2012 01:48:01 by Æthelwulf »
Logged
 

Offline Æthelwulf

  • Sr. Member
  • ****
  • 358
  • Activity:
    0%
Re: Force of impact question
« Reply #2 on: 27/04/2012 18:50:33 »
Quote from: willpower on 27/04/2012 15:51:42
I drop a 1kg weight from a meter in height and it decelerates to a stop in 0.1 of a meter (total distance travelled 1.1 meters)
What force is applied to the impact object?
What force is applied to the falling object? (assuming no deformation)
All assuming no air resistance and no bouncing


Why is your question expressing weight in kilograms, that is the unit for mass. Weight is expressed traditionally in Newtons?
Logged
 

Offline imatfaal

  • Naked Science Forum King!
  • ******
  • 2782
  • Activity:
    0%
  • Thanked: 1 times
  • rouge moderator
Re: Force of impact question
« Reply #3 on: 27/04/2012 18:59:00 »
Quote from: Æthelwulf on 27/04/2012 18:50:33
Quote from: willpower on 27/04/2012 15:51:42
I drop a 1kg weight from a meter in height and it decelerates to a stop in 0.1 of a meter (total distance travelled 1.1 meters)
What force is applied to the impact object?
What force is applied to the falling object? (assuming no deformation)
All assuming no air resistance and no bouncing


Why is your question expressing weight in kilograms, that is the unit for mass. Weight is expressed traditionally in Newtons?

http://en.wiktionary.org/wiki/weight

You should check out def no.s 2,3 &5.  Weight in the OP is being used as a concrete noun - ie a lump of metal of known mass.
Logged
There’s no sense in being precise when you don’t even know what you’re talking about.  John Von Neumann

At the surface, we may appear as intellects, helpful people, friendly staff or protectors of the interwebs. Deep down inside, we're all trolls. CaptainPanic @ sf.n
 

Offline Æthelwulf

  • Sr. Member
  • ****
  • 358
  • Activity:
    0%
Re: Force of impact question
« Reply #4 on: 27/04/2012 19:26:01 »
Quote from: imatfaal on 27/04/2012 18:59:00
Quote from: Æthelwulf on 27/04/2012 18:50:33
Quote from: willpower on 27/04/2012 15:51:42
I drop a 1kg weight from a meter in height and it decelerates to a stop in 0.1 of a meter (total distance travelled 1.1 meters)
What force is applied to the impact object?
What force is applied to the falling object? (assuming no deformation)
All assuming no air resistance and no bouncing


Why is your question expressing weight in kilograms, that is the unit for mass. Weight is expressed traditionally in Newtons?

http://en.wiktionary.org/wiki/weight

You should check out def no.s 2,3 &5.  Weight in the OP is being used as a concrete noun - ie a lump of metal of known mass.

Oh right. Ok.
Logged
 



Offline Æthelwulf

  • Sr. Member
  • ****
  • 358
  • Activity:
    0%
Re: Force of impact question
« Reply #5 on: 27/04/2012 19:32:02 »
Quote from: Æthelwulf on 27/04/2012 19:26:01
Quote from: imatfaal on 27/04/2012 18:59:00
Quote from: Æthelwulf on 27/04/2012 18:50:33
Quote from: willpower on 27/04/2012 15:51:42
I drop a 1kg weight from a meter in height and it decelerates to a stop in 0.1 of a meter (total distance travelled 1.1 meters)
What force is applied to the impact object?
What force is applied to the falling object? (assuming no deformation)
All assuming no air resistance and no bouncing


Why is your question expressing weight in kilograms, that is the unit for mass. Weight is expressed traditionally in Newtons?

http://en.wiktionary.org/wiki/weight

You should check out def no.s 2,3 &5.  Weight in the OP is being used as a concrete noun - ie a lump of metal of known mass.

Oh right. Ok.

So really

1kilogram of mass  as we know is 9.81 newtons thus I suppose, 1kg = 9.81 newtons and since 1 newton is 0.101971621 kilogram of force then 1 kilogram of force is 9.80665 newton.
Logged
 

Offline Geezer

  • Naked Science Forum King!
  • ******
  • 8314
  • Activity:
    0%
  • Thanked: 8 times
  • "Vive la résistance!"
Re: Force of impact question
« Reply #6 on: 27/04/2012 20:53:34 »
Quote from: Æthelwulf on 27/04/2012 19:32:02

1kilogram of mass  as we know is 9.81 newtons thus I suppose, 1kg = 9.81 newtons and since 1 newton is 0.101971621 kilogram of force then 1 kilogram of force is 9.80665 newton.


1kg (mass) exerts a force of around 9.81N in standard Earth gravity (your measured force might vary).

Logged
There ain'ta no sanity clause, and there ain'ta no centrifugal force æther.
 



  • Print
Pages: [1]   Go Up
« previous next »
Tags:
 
There was an error while thanking
Thanking...
  • SMF 2.0.15 | SMF © 2017, Simple Machines
    Privacy Policy
    SMFAds for Free Forums
  • Naked Science Forum ©

Page created in 0.356 seconds with 43 queries.

  • Podcasts
  • Articles
  • Get Naked
  • About
  • Contact us
  • Advertise
  • Privacy Policy
  • Subscribe to newsletter
  • We love feedback

Follow us

cambridge_logo_footer.png

©The Naked Scientists® 2000–2017 | The Naked Scientists® and Naked Science® are registered trademarks created by Dr Chris Smith. Information presented on this website is the opinion of the individual contributors and does not reflect the general views of the administrators, editors, moderators, sponsors, Cambridge University or the public at large.