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The simple and perhaps most illuminating answer is that when you add velocities, a simple sum does not give the right answer.If you add two velocities (along one direction), v(total) = v(1) + v(2) – v(1)*v(2)/cIf v is much smaller than c, you can see that velocities will add up as you expect, but when you get close to c, then they do not.Examples: v(1) = v(2) = 0.01 c; v(total) = 0.0199 c -- not 0.02 cv(1) = v(2) = 0.5 c; v(total) = 0.75 c -- not cv(1) = v(2) = 0.9 c; v(total) = 0.99 c -- not 1.8 c
c remains constant because time compensates in just the right manner to keep it so.
Quote from: damocles on 08/04/2012 02:48:04Quote from: MikeS on 08/04/2012 10:10:53c remains constant because time compensates in just the right manner to keep it so. Remember that distance is also changed thru a lorentz transform - its not just time that changesTrue, and that affects the length of the spaceship but I believe not the surrounding space which is not moving (apart from any small frame dragging effect). So, just time adjusting in just the right manner is sufficient to keep c constant without taking into account length contraction. Also I think I am correct in saying that you either take into account time contraction or length contraction, not both at the same time.
Quote from: MikeS on 08/04/2012 10:10:53c remains constant because time compensates in just the right manner to keep it so. Remember that distance is also changed thru a lorentz transform - its not just time that changes