[guest39538]

In an x,y  52*52 array

y52
...............................................
..............................................
..............................................
.............................................
............................................x52


Where all x (each row) contains 52 of the same variables. (each row all contain 52 playing cards spread out )


In a random shuffle of all rows.   

Where you receive the most left aligned value

The probability of a repeat value from any row x is 1/52?   

Now if we were to re-align  to any y-axis, and we were to randomly pick any row, our chances of a repeat value are ?/52?

Y being a totally independent choice of x and having the possibility of more , equal to or less, than 1/52 of any card.

Shown in a minimal array

yy
12x
12x

x Δ y = ΔP where P is the probability of a repeat

In the above minimal example  when we use the first column

All x = 1/2

x Δ y
y
1
1

=2/2 chance of a repeat

If we already received a 1.

Does anyone disagree?

[guest39538]

Help me out guys please, I need some probability info.


All {a}x = 1/52

All {a}y = ?/52


y52
.
.
.
................x52


In a 52*52 array where all x rows are randomly shuffled to make the columns y.

?


P {a}/y = var (1/52)x